Answer:
5x+2y =-6 ........1
3x-2y = 22 ........2
Add both Equations
we get
8x = 16
Divide both sides by 8
x = 2
Substitute x = 2 into any of the equations
3(2) - 2y = 22
-2y = 22 - 6
- 2y = 18
Divide both sides by -2
y = - 9
x = 2 y = - 9
Hope this helps
minimum value: 1
lower quartile: 3
median of the data: 6
upper quartile: 8
maximum value: 14
Sorry for the late answer, i hope this will help you in the future and everyone else who reads this.
Answer:
Period ⇒ 40
Amplitude ⇒ 12
Mid-line ⇒ 32
Step-by-step explanation:
The table is counting by 4's and the period is the amount of space between 2 peaks. In this scenario, we can find the peaks by looking for two of the same highest value (44). We can see that x=40 has a value of 44 while the other is actually not shown because it would be located at x=0. Therefore the period is 40
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The amplitude can be found by using the following:
Our maximum is 44 and our minimum is 20.
The amplitude is 12
The amplitude is the distance from the peak to the mid-line. To find the mid-line, we can either subtract our amplitude from our maximum value (44) or add our amplitude to our minimum value (20)
44 - 12 = 32
20 + 12 = 32
Therefore our mid-line is y = 32
~Hope this helps!~
We have (3/4)^2 + (
/4)^2 = 9/16 + 7/16 = (9+7)/16 = 16/16 = 1.
The answer is yes.
Answer: x = -2
Step-by-step explanation: 3x+7 = -x-1; add 1 to both sides: 3x+8=-x; subtract 3x from both sides: 8 = -4x; divide by -4 on both sides: -2 = x