For this case we have a function of the form 
, where
To find the real zeros we must equal zero and clear the variable "x".
We add 10 to both sides of the equation
We apply cube root to both sides of the equation:
![\sqrt[3]{(x-12)^3} = \sqrt[3] {10}\\x-12 = \sqrt[3] {10}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%28x-12%29%5E3%7D%20%3D%20%5Csqrt%5B3%5D%20%7B10%7D%5C%5Cx-12%20%3D%20%5Csqrt%5B3%5D%20%7B10%7D)
We add 12 to both sides of the equation:
![x-12 + 12 = \sqrt[3] {10} +12\\x = \sqrt[3] {10} +12](https://tex.z-dn.net/?f=x-12%20%2B%2012%20%3D%20%5Csqrt%5B3%5D%20%7B10%7D%20%2B12%5C%5Cx%20%3D%20%5Csqrt%5B3%5D%20%7B10%7D%20%2B12)
Answer:
Option D
Answer:
step 2
Step-by-step explanation:
from -8(a+6) to -80 - 48 is incorrect
when you multiply -8 x a it's -8a not -80
Answer:
a. 100.48
Step-by-step explanation:
c = r(pi)(2)
r = 16 m
pi = 3.14
16 x 3.14 = 50.24
50.24 × 2 = 100.48
Answer:
Lol
Step-by-step explanation:
