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skelet666 [1.2K]
3 years ago
13

Which table shows the function y = -2x + 4? A) x y 0 4 1 2 2 0 B) x y 1 25 2 26 3 27 C) x y 0 -4 1 -2 2 0 D) x y -1 6 -2 8 -3 12

Mathematics
1 answer:
Svet_ta [14]3 years ago
4 0
The answer is A.

From looking at the A graph, you must plug in the x variable into<span> y = -2x + 4.

y = -2(0) + 4 = 4
y = -2(1) + 4 = 2
y = -2(2) + 4 = 0</span>
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h(n)=-13nh(n)=−13nh, left parenthesis, n, right parenthesis, equals, minus, 13, n Complete the recursive formula of h(n)h(n)h, l
mr Goodwill [35]

Answer:

h(1)=-13

h(n)=h(n-1)-13, n\geq 2

Step-by-step explanation:

We are given that

h(n)=-13n

We have to find the recursive formula of h(n).

Substitute n=1

h(1)=-13

n=2

h(2)=-13-13=-26=h(1)-13

n=3

h(3)=-13(3)=-39=-26-13=h(2)-13

h(4)=-13(4)=-52=-39-13=h(3)-13

:

:

:

h(n)=h(n-1)-13

Therefore, the recursive formula is given by

h(1)=-13

h(n)=h(n-1)-13, n\geq 2

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A team of bakers can roll and form 5 dozen pretzels in 9 minutes. How many pretzels can this team form in 1 hour?
tino4ka555 [31]
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The expression 12 x y z - 45 is a what
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the 11th term in a geometric sequence is 48 and the common ratio is 4. the 12th term is 192 and the 10th term is what?
Soloha48 [4]

<u>Given</u>:

The 11th term in a geometric sequence is 48.

The 12th term in the sequence is 192.

The common ratio is 4.

We need to determine the 10th term of the sequence.

<u>General term:</u>

The general term of the geometric sequence is given by

a_n=a(r)^{n-1}

where a is the first term and r is the common ratio.

The 11th term is given is

a_{11}=a(4)^{11-1}

48=a(4)^{10} ------- (1)

The 12th term is given by

192=a(4)^{11} ------- (2)

<u>Value of a:</u>

The value of a can be determined by solving any one of the two equations.

Hence, let us solve the equation (1) to determine the value of a.

Thus, we have;

48=a(1048576)

Dividing both sides by 1048576, we get;

\frac{3}{65536}=a

Thus, the value of a is \frac{3}{65536}

<u>Value of the 10th term:</u>

The 10th term of the sequence can be determined by substituting the values a and the common ratio r in the general term a_n=a(r)^{n-1}, we get;

a_{10}=\frac{3}{65536}(4)^{10-1}

a_{10}=\frac{3}{65536}(4)^{9}

a_{10}=\frac{3}{65536}(262144)

a_{10}=\frac{786432}{65536}

a_{10}=12

Thus, the 10th term of the sequence is 12.

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3 years ago
Easy math problems!!!!!
Alexandra [31]

Answer: 36

Step-by-step explanation:

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