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kolezko [41]
3 years ago
15

Find a system of two equations in two variables, x1 and x2, that has the solution set given by the parametric representation x1

= t and x2 = 5t − 6, where t is any real number. (Enter your answer as a comma-separated list of equations.)
Mathematics
1 answer:
Crazy boy [7]3 years ago
3 0

Answer:

The required system of equations to the given parametric equations are:

5x1 - x2 = 6

x1 + x2 = -6

Step-by-step explanation:

Given the parametric equations:

x1 = t

x2 = -6 + 5t

Eliminating the parameter t, we obtain one of the equations of a system in two variables, x1 and x2 that has the solution set given by the parametric equations.

Doing that, we have:

5x1 - x2 = 6

Again a second equation can be a linear combination of x1 and x2

x1 + x2 = -6 + 6t

x1 + x2 = -6 (putting t=0)

And they are the required equations.

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The quotient of (x4 + 5x3 – 3x – 15) and a polynomial is (x3 – 3). What is the polynomial?
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Answer:

g(x) = x+5

Step-by-step explanation:

Given that,

f(x)=x^4+5x^3-3x-15

q(x) = (x^3-3)

We need to find the polynomial. We know that, Euclid division lemma states that

f(x)=q(x)\times g(x)+r(x)

Where

f(x) is dividend

g(x) is the poynomial

q(x) is quotient

r(x) is remainder

So,

x^4+5x^3-3x-15=(x^3-3)\times g(x) +0\\\\g(x)=\dfrac{x^4+5x^3-3x-15}{(x^3-3)}\\\\g(x)=x+5

So, the polynomial is (x+5).

 

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