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3 years ago

Interior angle of a regular polygon is 160 why does it need 18 sides

Mathematics

1 answer:

hjlf3 years ago

8 0

Https://www.mathsisfun.com/geometry/interior-angles-polygons.html

Are you familiar with that?

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HURRY I NEED THE ANSWER NOW

lutik1710 [3]

Answer: The correct answer is 5

5 0

2 years ago

Read 2 more answers

12) Write the equation of a rational function

aev [14]

Answer:

$\frac{4(x - 5)(x + 7)(x - 12)}{(x + 1)(x)(x - 12)}$

Step-by-step explanation:

A rational function is

$\frac{p(x)}{q(x)}$

where q(x) doesn't equal zero.

If p is a asymptote, or hole at that value, then we will use

$(x - p)$

Step 1: We have asymptote as 0 and -1 so our denomiator will include

$(x - 0)(x - ( - 1)$

Which is

$(x)(x + 1)$

So our denomator so far is

$\frac{p(x)}{x(x + 1)}$

Step 2: Find Holes.

Since 12 is the value of the hole,

$(x - 12)$

is a the binomial.

This will be both on the numerator and denomator so qe have

$\frac{(x - 12)}{x(x + 1)(x - 12)}$

Step 3: Put the x intercepts in the numerator.

Since 5 and -7 is the intercepts,

$\frac{(x - 12)(x - 5)(x + 7)}{x(x + 1)(x - 12)}$

Step 4: Horinzontal Asymptotes,

Multiply the numerator and denomiator out fully,

$\frac{ {x}^{3} - 10 {x}^{2} - 59x + 420 }{ {x}^{3} - 12 {x}^{2} + x - 12}$

Take a L

look at the coefficients,

Notice they have the same degree,3, this means if we divide the leading coefficents, we will get our horinzonral asymptote.

Multiply the numerator by 4.

$\frac{4(x - 12)(x - 5)(x - 7)}{x(x + 1)(x - 12)}$

Above is the function,

5 0

2 years ago

Of the 50 plays attributed to a playwright, 11 are comedies, 19 are tragedies, and 20 are histories. If one play is selected

Cerrena [4.2K]

The answer is 3/5, or 60%

11 (comedies) + 19 (tragedies) = 30
30/50 = 3/5, or 60%

3 0

3 years ago

What does 7 grams equal

barxatty [35]

Answer: 7 grams is equal to 7×10^-3kg

Step-by-step explanation: One thousand grams is equal to one kilogram. To get the answer we have to divide 7 by 1000 to get the answer in kg.

5 0

3 years ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

6 0

1 year ago