Answer:
no of success deemed to be usual 5
that is more than 5 success unusual
Step-by-step explanation:
Given data
number of successes = less than μ − 2.5σ
number of successes = greater than μ + 2.5σ
trials n = 10
probability single trial = 0.2
to find out
is it unusual to have more than five successes
solution
we can say that
mean of the binomial, distribution that is
mean = probability single trial × trials n
mean = 10 × .2
mean = 2
and standard deviation = √(mean× (1-probability))
standard deviation = √2× (1-0.2))
standard deviation = 1.2649
so no of successes are
= μ − 2.5σ and = μ + 2.5σ
= 2 − 2.5(1.2649) and = 2 + 2.5(1.2649)
= -0.16225 and = 5.16225
so now we say no of success deemed to be usual 5
that is more than 5 success unusual here
