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Andre45 [30]
3 years ago
8

How do I find the value of K?

Mathematics
1 answer:
adelina 88 [10]3 years ago
6 0
<span>Determine the value of k such that g(x) = 3x + k intersects the quadratic function f(x) = 2x² - 5x + 3 at exactly one point. 
Hope this helps you:/</span>
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I need to find the value of x and y please help.
Marizza181 [45]

Answer:

x = -6.5 y= 3.75

Step-by-step explanation:

Add angle 1 and 2 since they are both alternate interior angles

6x + y - 4 = x - 9y + 1

- x  + 9y  - x  + 9y       Subtract x and add 9y to both sides

5x + 10y - 4 = 1          

             + 4 + 4           Add 4 to both sides

5x + 10y = 5

-5x            - 5x            Subtract 5x from both sides

10y = -5x + 5               Divide both sides by 10 to solve for y

y = -1/2x + 1/2        

Use this equation to solve for x in the original equations

6x + (1/2x + 1/2) -4 = x - 9(-1/2x +1) - 1

6.5x - 3.5 = x + 4.5x - 9 - 1      Solve in the parentheses

6.5x - 3.5 = 5.5x - 10               Solve the right side of the equation

        + 3.5           + 3.5             Add 3.5 to both sides

6.5x = 5.5x - 6.5

- 5.5x - 5.5x                             Subtract 5.5x from both sides

x = -6.5

Use the new value of x to solve for y

6(-6.5) + y -4 = -6.5 -9y + 1

-43 + y = -5.5 -9y         Simplify both sides

+43         + 43               Add 43 to both sides

y = 37.5 - 9y

+ 9y       + 9y                 Add 9y to both sides

10y = 37.5

y = 3.75

7 0
3 years ago
The polynomial 8x2-8x+2-5+x is simplified to 8x2-gx-h. What are the value of g and h?
fenix001 [56]
The answer for G=7 and H=3
Hope this helps!
8 0
3 years ago
Find the difference 7 7/8 - 3 1/4
lisov135 [29]
That would be 4 and 5/8. Because you would find the common denominator which would be 8 and then take 2*4 and 2*1 and get 2/8 and then subtract 3 and 2/8 from 7 and 7/8 and get 4 and 5/8. I hope this helps you.
3 0
3 years ago
The school is located where Wilson Street and Green Street intersect. Which ordered
blondinia [14]

(5,3) is the answer for the current question

4 0
3 years ago
Expand $\left(x^2 \frac{1}{x}\right)^3$. (Write the terms with higher degree first, so for example an $x^2$ term would come befo
Ilya [14]

Answer:

x^6+3x^3+3+\dfrac{1}{x^3}

Step-by-step explanation:

We can use the pascal triangle to find the coefficients of the expasion of the cube. It holds that

(x^2 + \dfrac{1}{x})^3=(x^2)^3+3(x^2)^2\dfrac{1}{x}+3x^2(\dfrac{1}{x})^2+(\dfrac{1}{x})^3\\\\=x^6+3x^4\dfrac{1}{x}+3x^2\dfrac{1}{x^2}+\dfrac{1}{x^3}\\\\=x^6+3x^3+3+\dfrac{1}{x^3}

4 0
3 years ago
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