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crimeas [40]
3 years ago
15

In 4-bit sign magnitude representation, what is the binary encoding of the number -5?

Computers and Technology
1 answer:
matrenka [14]3 years ago
5 0
Answer:B
Step-by-step explanation:
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An enhancement to a computer accelerates some mode of execution by a factor of 10. The enhanced mode is used 50% of the time, me
Ann [662]

Answer:

The answer is "5.5 and 90.90%"

Explanation:

For point 1:

To calculate the speed from fast mode, its run time without enhancement should be worked out. Designers are aware of which two selves are implicated throughout the accelerated project planning: the empty (50 \%) and the increased stages (50 \%).

Although not enhanced, this would take almost as long (50 \%) and for the combine to give phase; even so, the increased phase would've been 10 times longer, as well as 500 \%. Thus the corresponding total speed without enhancement is =50\% + 500\% = 550\%.

Its overall speed is:

=\frac{\text{Accelerated runtime}}{ \text{accelerated  runtime}} = \frac{550 \%}{ 100 \%}= 5.5

For point 2:

We re-connect these figures in Amdahl's Law throughout order to identify how long it would take for both the initial implementation:

\text{Vectorized fraction}= \frac{\text{Overall velocity}\times \text{Accelerated acceleration}-\text{Accelerated acceleration}}{\text{Overall acceleration} \times \text{Accelerated acceleration}-\text{Overall acceleration}}

                              = \frac{5.5  \times 10 -10 }{ 5.5 \times 10 - 5.5}\\\\=\frac{45}{49.5}\\\\=0.9090\\\\=90.90\%

5 0
2 years ago
The measure of the maximum amount of data that can travel through a computer’s communications path in a given amount of time is
STatiana [176]

Answer:

Bandwidth

Explanation:

Bandwidth is the rate of transfer of data in the given time. Its unit is Bit/sec.

It is used to measure the transfer rate of bit in a network.

4 0
3 years ago
When planning the structure of a spreadsheet, columns are for _______ items and rows are for _______ items.
Alisiya [41]
I believe the correct answer from the choices listed above is option D. <span>When planning the structure of a spreadsheet, columns are for group items and rows are for single items. Hope this answers the question. Have a nice day.</span>
5 0
2 years ago
Read 2 more answers
Part B - Find the solutions for the following Case Study Real World Problems by applying the appropriate concepts that you learn
Monica [59]

Answer:

ok very surprised to hear that

5 0
3 years ago
In this lab, you complete a C++ program that swaps values stored in three int variables and determines maximum and minimum value
Sergio039 [100]

Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

int main()//main method

{

int first = 0,second = 0,third = 0;//defining integer variable  

int temp; //defining integer variable

const string SENTINEL = "done"; // defining a string variable as constant  

string repeat;// defining a string variable  

bool notDone = true; //defining bool variable

cout << "Enter first number: ";//print message

cin >> first;//input value

cout << "Enter second number: ";//print message

cin >> second;//input value

cout << "Enter third number: ";//print message

cin >> third;//input value

while(notDone == true)//defining a loop to check the value  

{

if(first > second)//use if to compare first and second value

{

int temp = first;//defining temp to hold first value

first = second;//holding second value in first variable

second = temp;//holding temp value in second variable

}

if(second > third)//use if to compare second and third value

{

int temp = second;//defining temp to hold second value

second = third;//holding second value in third variable

third = temp;//holding temp value in third variable

}

cout << "Smallest: " << first << endl;//print smallest value

cout << "Next smallest: " << second << endl;//print Next smallest value

cout << "Largest: " << third << endl;////print Largest value

cout << "Enter any letter to continue or done to quit: ";//print message

cin >> repeat;//holding string value

if (repeat == SENTINEL)

{

notDone = false;//holding bool value

}  

else //else block

{

cout << "Enter first number: ";//print message

cin >> first;//input value

cout << "Enter second number: ";//print message

cin >> second;//input value

cout << "Enter third number: ";//print message

cin >> third;//input value

}

return 0;

}

}

Output:

Please find the attached file.

Explanation:

  • Inside the main method Four integer variable "first, second, third, and temp" is declared in which first three variable is used for input value and temp is used to compare value.
  • In thew next step, two string variable "SENTINEL and repeat" is declared in which "SENTINEL" is constant and a bool variable "notDone" is declared.
  • After input the value from the user-end a loop is declared that compare and swap value and print its value.

6 0
3 years ago
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