All categories

1 year ago

Computers rarely make mistakes. True or false

Computers and Technology

1 answer:

Angelina_Jolie [31]1 year ago

3 0

Answer: False, everything makes mistakes, even technology.

Explanation: It's not rare for a computer to slip up and glitch. All you need to do is troubleshoot it. Hope this helps :)

You might be interested in

Imagine the user types in a complete sentence, but we want to read only the first word and place it in the String variable word.

Vladimir [108]

Answer:

import java.util.Scanner;

public class FirstWord {

public static void main(String[] args) {

//NOW YOU WANT TO COLLECT INPUTS FROM THE STUDENT OR USER

//IMPORT THE SCANNER CLASS FIRST outside your class

// THEN YOU CREATE AN OBJECT OF THE SCANNER CLASS

Scanner input = new Scanner(System.in);

//CREATE A VARIABLE TO HOLD THE USER INPUT

String text = input.nextLine();

//The variable holder will be used to store characters from the for loop

String holder="";

//Create a for loop that loops through the user's input

for(int i=0; i<text.length(); i++){

//As the loop increases, we get the character in the user's input and store them one by one in the variable holder

holder+=text.charAt(i);

if(text.charAt(i)==' '){

//If the loop encounters a space, it means a complete word has been gotten from the user's input

//Then the break below Breaks the loop, and the loop stops running

break;

}

System.out.println(holder);

}

Explanation:

text.length() returns the length of the sequence of characters present in length

text.charAt(a number) Returns the char value at the specified index. An index ranges from 0 to length() - 1. The first char value of the sequence is at index 0, the next at index 1, and so on, as for array indexing.

Create a for loop

How does a for loop work?

It collects a starting point, an end point and an increment respectively....all these are passed in as arguments into the for loop

For example, the code above starts from 0, calculates the number of characters in the user's input and sets it as the end point, the loop runs from zero to the length of the text of the user...

Note: i++ in the loop is the increment, it means the loop increases by 1

8 0

3 years ago

Which of the following factors wouldn't change an account's optimization score?

MatroZZZ [7]

Answer:

Renaming Campaigns

Explanation:

Based on the information provided within the question it can be said that the factor that wouldn't change this would be Renaming Campaigns. This is because an account's optimization score is an estimate of how well the account/campaign will perform in the near future. Changing the name will not change this score since the campaign is still following the same strategy and therefore the estimates will be the same.

8 0

3 years ago

Write a program that converts a number entered in Roman numerals to decimal. your program should consist of a class, say, Roman.

arlik [135]

Answer:

The code is given below in Java with appropriate comments

Explanation:

import java.util.*;

public class RomantoDecimal {

public static void main(String[] args)

{

Scanner SC = new Scanner(System.in);

RomantoDecimal r = new RomantoDecimal();

System.out.println("Enter a Roman number :");

// INPUT A ROMAN NUMBER

String rNum = SC.next();

// CALL convertToDecimal FOR CONVERSION OF ROMAN TO DECIMAL

r.convertToDecimal(rNum);

}

// M=1000, D=500, C=100, L=50, X=10, V=5, I=1

public void convertToDecimal(String roamNo)

{

int number = 0;

// TEACK EACH DIGIT IN THE GIVEN NUMBER IN REVERSE ORDER

for (int i = roamNo.length() - 1; i >= 0; i--)

{

// FIND OUT WHETHER IT IS 'M' OR NOT

if (roamNo.charAt(i) == 'M')

{

if (i != 0)

{ // CHECK WHETHER THERE IS C BEFORE M

if (roamNo.charAt(i - 1) == 'C')

{

number = number + 900;

i--;

continue;

}

number = number + 1000;

}

// FIND OUT WHETHER IT IS 'D' OR NOT

else if (roamNo.charAt(i) == 'D')

{

if (i != 0)

{

// CHECK WHETHER THERE IS C BEFORE D

if (roamNo.charAt(i - 1) == 'C')

{

number = number + 400;

i--;

continue;

}

number = number + 500;

}

// FIND OUT WHETHER IT IS 'C' OR NOT

else if (roamNo.charAt(i) == 'C')

{

if (i != 0)

{

if (roamNo.charAt(i - 1) == 'X')

{

number = number + 90;

i--;

continue;

}

number = number + 100;

}

else if (roamNo.charAt(i) == 'L')

{

if (i != 0)

{

if (roamNo.charAt(i) == 'X')

{

number = number + 40;

i--;

continue;

}

number = number + 50;

}

// FIND OUT WHETHER IT IS 'X' OR NOT

else if (roamNo.charAt(i) == 'X')

{

if (i != 0)

{

if (roamNo.charAt(i - 1) == 'I')

{

number = number + 9;

i--;

continue;

}

number = number + 10;

}

// FIND OUT WHETHER IT IS 'V' OR NOT

else if (roamNo.charAt(i) == 'V')

{

if (i != 0)

{

if (roamNo.charAt(i - 1) == 'I')

{

number = number + 4;

i--;

continue;

}

number = number + 5;

}

else // FIND OUT WHETHER IT IS 'I' OR NOT

{

number = number + 1;

}

}// end for loop

System.out.println("Roman number: " + roamNo + "\nIts Decimal Equivalent: " + number);

}

3 0

3 years ago

The best way for employees to improve their skills online is to enroll in a digital

Maksim231197 [3]

The best way for employees to improve their skills online is to enroll in a digital office.

office.

<u>Explanation:</u>

In the present innovation-driven world, upskilling is turning out to be progressively significant just in light of the fact that innovation changes so quick.

A key preferred position for workers in web-based learning is that representatives can finish their preparation voluntarily and as indicated by their own timetables.

Enrolling in a digital office would allow an individual to learn at their ease, pace and comfort. It will definitely help the individual to expand and acquire skills.

So now full-time workers or the individuals who essentially don't have the opportunity to return to college full-time have a lot of chances to discover low maintenance courses.

6 0

3 years ago

Read 2 more answers

Paul is a baker who wants to improve his recipe for muffins because they turn out with a greasy flavor. What ingredient should h

Sergio039 [100]

Butter to Margarine

Cakes baked with butter usually always turns out to be greasy and heavy.

Hope this helps, good luck! (:

3 0

3 years ago

Read 2 more answers