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djverab [1.8K]
3 years ago
10

If a person making $35 an hour gets a 10% raise, how much will that person now make in a 6 hour day

Mathematics
1 answer:
Montano1993 [528]3 years ago
4 0

Answer:

$231 over a 6 hour period

Step-by-step explanation:

the person is already making $35

10% of $35 is 3.50

$35 + $3.50 = $38.50 per hour

$38.50 x 6 hours = $231

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Veronika [31]

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Compare 0.55 ____ 0.525 using , or =
fredd [130]

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0.55 > 0.525

Step-by-step explanation:

3 0
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Can some one help me solve this?
garik1379 [7]

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5 0
3 years ago
A town has a population of 13000 and grows at 4.5% every year. To the nearest tenth of a year, how long will it be until the pop
ELEN [110]

Answer:

Correct answer: n = 5.96 ≈ 6 years

Step-by-step explanation:

Given:

Currently population P = 13,000

The percentage annual population growth is 4.5 % or in decimal notation

p = 1.045

Population after n years  Pₙ = 16,900

Work:

After first year it will be   P₁ = P · p

After second year it will be   P₂ = P₁ · p = P · p²

After third year it will be   P₃ = P₂ · p² = P · p³

.....................................................................................

After n-th year it will be   Pₙ = P · pⁿ

pⁿ = Pₙ / P  

n = log p (Pₙ / P) = ln (Pₙ / P) / ln p

n = ln (16,900/ 13,000) / ln 1.045 = ln 1.3 / ln 1.045 = 5.96 ≈ 6

If we accept  n = 5.9 we will get:

Pₙ = P · pⁿ = 13.000 · 1.045⁵°⁹ = 16,855

If we accept  n = 5.96 we will get:

Pₙ = P · pⁿ = 13.000 · 1.045⁵°⁹⁶ = 16,899.6

If we accept  n = 6 we will get:

Pₙ = P · pⁿ =  P₆ = P · p⁶ = 13.000 · 1.045⁶ = 16,929.38

What you will accept is yours choice.

God is with you!!!

5 0
4 years ago
Read 2 more answers
The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic
Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 10

            r = number of success

            p = probability of success which in our question is % of first-round

                   appeals that were successful, i.e.; 40%

So, here X ~ Binom(n=10,p=0.40)

(a) Probability that none of the appeals will be successful = P(X = 0)

     P(X = 0) = \binom{10}{0}0.40^{0}(1-0.40)^{10-0}

                   = 1*0.6^{10} = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

     P(X = 1) = \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                  = 10*0.4^{1} *0.6^{10-1} = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

    P(X >= 2) = 1 - P(X = 0) - P(X = 1)

                     = 1 - \binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                     = 1 - 0.00605 - 0.0403 = 0.9536

(d) Probability that more than half of the appeals will be successful =             P(X > 0.5)

  For this probability we will convert our distribution into normal such that;

   X ~ N(\mu = n*p=4,\sigma^{2}= n*p*q = 2.4)

  and standard normal z has distribution as;

      Z = \frac{X-\mu}{\sigma} ~ N(0,1)

  P(X > 0.5) = P( \frac{X-\mu}{\sigma} > \frac{0.5-4}{\sqrt{2.4} } ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

3 0
3 years ago
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