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Alex_Xolod [135]
4 years ago
15

Involves triangle centroid

Mathematics
1 answer:
Rasek [7]4 years ago
6 0
Here, you do the same as the previous one, keeping in mind that X cuts TW in a 2:1 ratio.

\bf TW-TX=XW\implies \cfrac{8a}{5}+\cfrac{1}{10}-\left(a +\cfrac{4}{5} \right)=XW
\\\\\\
\cfrac{8a}{5}+\cfrac{1}{10}-a-\cfrac{4}{5}=XW\implies \cfrac{3a}{5}-\cfrac{7}{10}=XW\\\\
-------------------------------\\\\

\bf TX:XW\qquad 2:1\qquad \cfrac{TX}{XW}=\cfrac{2}{1}\implies \cfrac{a+\frac{4}{5}}{\frac{3a}{5}-\frac{7}{10}}=\cfrac{2}{1}
\\\\\\
\cfrac{\frac{5a+4}{5}}{\frac{6a-7}{10}}=\cfrac{2}{1}\implies \cfrac{5a+4}{5}\cdot \cfrac{10}{6a-7}=\cfrac{2}{1}\implies \cfrac{10a+8}{6a-7}=\cfrac{2}{1}
\\\\\\
10a+8=12a-14\implies 22=2a\implies \cfrac{22}{2}=a\implies 11=a
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What is the sum of forty-six and ninety-four?
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Given 15 cot A = 8, find sin A and sec A.​
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The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

Step-by-step explanation:

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