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elixir [45]
3 years ago
6

Please help Evaluate the expression for n=2 4(n+1)=

Mathematics
2 answers:
Eduardwww [97]3 years ago
8 0

Answer:

substitute n in bigger equation with 2.

4(2+1)

4×3=12

Helen [10]3 years ago
5 0

Answer:

12

Step-by-step explanation:

4(2+1)

4*3

12

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What is the product of (2x-1)(x+4)
Novay_Z [31]

Answer:

\large\boxed{(2x-1)(x+4)=2x^2+7x-4}

Step-by-step explanation:

(2x-1)(x+4)\qquad\text{use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\=(2x)(x)+(2x)(4)+(-1)(x)+(-1)(4)\\\\=2x^2+8x-x-4\qquad\text{combine like terms}\\\\=2x^2+(8x-x)-4\\\\=2x^2+7x-4

4 0
3 years ago
A cube with an edge of length has a volume of 64 units. What is the length of ? Hint: Volume of a cube is LxWxH.
aleksandr82 [10.1K]

Answer:

it is 4

Step-by-step explanation:

5 0
2 years ago
Rowena can paint a room in $14$ hours, while Ruby can paint it in $6$ hours. If Rowena paints for $x$ hours and Ruby paints for
miv72 [106K]

Question

Rowena can paint a room in 14 hours, while Ruby can paint it in 6 hours. If Rowena paints for x hours and Ruby paints for y hours, they will finish half of the painting, while if Rowena paints for y hours and Ruby paints for x hours they will paint the whole room. Find the ordered pair (x,y)

Answer:

(x, y) = (231/40, 21/40)

where x = 231/40

y = 21/40

Step-by-step explanation:

From the question, we are told:

Rowena can paint a room in = 14 hours

Ruby can paint it in = 6 hours.

This means

In one hour.

Rowena can paint = 1/14 of the room

Ruby can paint =1/6 hour of the room

From the question, we are told that :

If Rowena paints for x hours and Ruby paints for y hours, they will finish half of the painting

This is represented mathematically as:

(1/14)(x) + ( 1/6)(y) = 1/2...... Equation 1

Also we were told that:

if Rowena paints for y hours and Ruby paints for x hours they will paint the whole room

(1/14)(y) + (1/6)(x) = 1 .......... Equation 2

Bringing the two equations together, we have:

(1/14)(x) + ( 1/6)(y) = 1/2 ....... Equation 1

(1/14)(y) + (1/6)(x) = 1 ............ Equation 2

We find the Lowest common multiple of the numerator 14 and 6 = 42. Hence, we multiply both equations through by 42

3x + 7y = 21 ....... Equation 3

7x + 3y = 42 ......... Equation 4

To solve for x and y in Equation 3 and 4 we would be using the Elimination method

21x + 49y = 147 .......... Equation 5

21x +9y = 126 ........... Equation 6

21x + 49y = 147 .......... Equation 5

-(21x +9y = 126) ........... Equation 6

40y = 21

y = 21/40

To get the value of x , we would substitute 21/40 for y in Equation 3

3x + 7y = 21 ....... Equation 3

3x + 7(21/40) = 21

3x + 147/40 = 21

3x = 21 - 147/40

3x = 693/40

x = (693/40) ÷ 3

x = 693/40 × 1/3

x = 693/120

x = 231/40

Therefore, (x, y) = (231/40, 21/40)

7 0
3 years ago
A parabola can be drawn given a focus of (0,−6) and a directrix of y=−2. Write the equation of the parabola in any form.
topjm [15]

Answer:

y = x^2 - 4

Step-by-step explanation:

The vertex of a parabola is exactly halfway between the focus and the directrix.  If the focus is at (0, -6) and the directrix is the line y = -2, then we do this to locate the vertex:  Draw a vertical line through (0, -6) also crossing the line y = -2.  The y value halfway between y = -6 and y = -2 is y = -4, and the vertex is thus (0, -4).

Using the vertex method, write out the equation of this parabola, starting with the general form y - k = (x-h)^2, where (h, k) is the vertex.  Here h = 0 and k = -4

We get:  y + 4 = (x - 0)^2, or y + 4 = x^2, or y = x^2 - 4.  As a check, let x = 0; y = -4, which is the y-coordinate of the vertex.

7 0
2 years ago
Given: ∠BCD ≅ ∠EDC and ∠BDC ≅ ∠ECD Prove: Δ BCD ≅ Δ EDC
weeeeeb [17]
I think this is right.

8 0
3 years ago
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