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Kobotan [32]
3 years ago
15

Given: ∠BCD ≅ ∠EDC and ∠BDC ≅ ∠ECD Prove: Δ BCD ≅ Δ EDC

Mathematics
1 answer:
weeeeeb [17]3 years ago
8 0
I think this is right.

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I need help with this problem <br><br><br> -8(2v-2)=-4(7+5v)
Ne4ueva [31]

Answer: I'm not sure if this is right or not but I got U = 4

Step-by-step explanation: -8(2v-2)=-4(7+5u. So first I distributed and got -16v -16 = 28 + 20u. And then I added 16u with 20u I added because you change the sign like if it's a negative you make it a positive so once you do 20u+16v you should get 36 and then on the other side it should be -16+16 which equals -16u from when you distributed so now you should have -16u=28+36 so now you would add 28 the 36 since they both are positives and have no variables which you should get 64 and then on the left you should have 16u. So it looks like -16u=64. And then now you would divide -16u on both sides and the side with the variable put it or v whatever variable you want to use and then do 64 divided by 16 and you should get 4.

6 0
4 years ago
Can someone please help mee (will give brainliest 20 points!!!)
Mice21 [21]

  [a] x = 175 - 7.5p

For a, we are isolating the x variable to one side of the equation.

        0.4x + 3p = 70

        0.4x = - 3p + 70

        x =  - 7.5p + 175

  [b] x = 115

For b, we are solving for x when p = 8.

        x =  - 7.5p + 175

        x =  - 7.5(8) + 175

        x = 115

7 0
2 years ago
Find the perimeter 5 1\2
Shkiper50 [21]

Answer:

22

Step-by-step explanation:

6 0
3 years ago
Divide the number in the thousands place by itself and then multiply the answer by 0. Write your answer in the tenths place
Ivanshal [37]
Number: 1111
1111/1111=1
1*0= 0
Now put 0 in the tenths place
01

Hope this Helped :)
5 0
3 years ago
The length of a rectangle is represented by the function L(x) = 5x. The width of that same rectangle is represented by the funct
Mazyrski [523]

Remember that the area of a rectangle is the length of the rectangle multiplied by the width of the rectangle.


In this case, we could say (where A(x) is the area of the rectangle):

A(x) = L(x) \cdot W(x)


Substituting the values the problem gave us for L(x) and W(x), we can find the formula for A in terms of x, which is:

A(x) = (5x) \cdot (2x^2 - 4x + 13) = (10x^3 - 20x^2 + 65x)


The formula for the area of the rectangle would be A(x) = 10x³ - 20x² + 65x.

3 0
3 years ago
Read 2 more answers
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