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OLEGan [10]
3 years ago
7

Sophia and her friends are planning to spend the day at the zoo. It will cost her $12.75 for admission and $2.50 for each ticket

to see the exhibits. She has $50 total to spend.
Mathematics
1 answer:
lukranit [14]3 years ago
4 0
Sofia would have $34.75 left
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Use a net to find the lateral area and the total surface area of the cereal box.
ziro4ka [17]
To find the lateral area you will find the area of all 4 faces that are perpendicular to the base.

You will multiply the side by the length (front/back) and the side by the width (sides).

12 x 8 = 96
12 x 2 = 24
120 square inches x 2 = 240 square inches

The lateral area is 240 square inches.

The area of the base is 8 x 2 = 16 square inches.

16 x 2 = 32 square inches

240 square inches + 32 square inches = 272 square inches is the surface area.
7 0
3 years ago
$5,000 is invested at 3% interest.
adell [148]
5000*0.03+0.05x=275
Solve for x
X=2500
The answer is b
4 0
3 years ago
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I need help and it’s due today
frez [133]

Answer:

5.63

Step-by-step explanation:

Angle NLM is equal to KLM - KLN.

Since KLM = 137° and KLN = 47°, NLM = °90. (Maybe it doesn't look like a right angle, but the math doesn't lie.)

Since NLM = 16y, then 90 = 16y.

Dividing both sides by 16, we find that:

y = 5.625

5 0
3 years ago
Read 2 more answers
An equation is shown below:
IrinaK [193]
5(2x - 8) + 15 = -15
               -15      -15     subtract 15 from each side
5(2x - 8) = -30
  ÷5             ÷5             divide both sides by 5
2x - 8 = -6
     +8    +8                   add 8 to each side
2x=2
÷2  ÷2                          divide both sides by 3
x = 1

Checking:
5(2(1)-8) + 15 = -15
5(-6) + 15 = -15
-30 + 15 = -15
-15 = -15             Correct! x=1
7 0
3 years ago
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How would you solve cos(5x)=sin(10x) ?
Tomtit [17]
We will use double angle identities:
cos (5x ) = sin (10x )   
cos (5x ) = 2 cos (5x ) sin ( 5x )
cos ( 5 x) - 2 cos ( 5 x ) sin ( 5x ) = 0
cos ( 5 x ) · [ 1 - 2 sin (5 x) ] = 0
cos ( 5 x ) = 0                    or :       1 - 2 sin (5 x) = 0
5 x = π/2 +kπ,  k∈Z                        sin (5 x) = 1/2
x1 = π/10 + kπ/5                           5 x = π/6+2kπ    , k∈ Z
                                                       5 x = 5π/6 +2kπ , k∈ Z
                                                       x 2 = π/30 +2kπ/5
                                                       x 3 = π/9  + 2kπ/5
4 0
3 years ago
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