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Llana [10]
2 years ago
15

Consider the following sequence -3; 2; 7; 12 Find an expression for the term Which term of the sequence with equal 77"}​

Mathematics
1 answer:
galina1969 [7]2 years ago
8 0

Answer: n77 into below

Step-by-step explanation:

N77 value = starting point + (77-1) x (5)

= -3 + (5)x76

U can do the calcs from here yeah?

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QveST [7]
1) x = - 4, y = - 12; (- 4, - 12)

2) x = 34, y = 17; (34, 17)

3) x = 16, y = 7; (16, 7)

4) x = 7, y = - 4; (7, - 4)

5) x = - 4, y = 10; (- 4, 10)

6) x = 12, y = - 7; (12, - 7)

7) x = 5, y = 10; (5, 10)

8) x = 11, y = - 12; (11, - 12)
8 0
2 years ago
BIG POINTS Please solve. Thanks!
Nitella [24]

9^1/3 * 3^x = 27^4/5

Rewrite 9 as 3^2

(3^2)^1/3 * 3^x = 27^4/5

Multiply the exponents in the first term:

3^2/3 * 3^x = 27^4/5

Use power rule to combine exponents:

3^(2/3 +x) = 27^4/5

Rewrite the 2nd term:

3^(2/3 +x) = (3^3)^4/5

Set the exponents only to equal:

2/3 + x = 3(4/5)

Solve for x:

simplify the right side:

2/3 + x = 12/5

Subtract 2/3 from both sides:

x = 26/15

3 0
3 years ago
Tamara has a cell phone plan that charges $0.07 per minute plus a monthly fee of $19.00. budgets $29.50 per month for total cell
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The answer is the letter A! I hope this helps
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A tiger can eat up to 55 pounds a meat a day about hiw many days would it take to eat the follwing pray
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2 years ago
What is the radius of the following circle?
lara [203]

Answer:

The radius is: 2\sqrt{3}

Step-by-step explanation:

The equation of a circle in center-radius form is:

(x - h)^2 + (y - k)^2 = r^2

Where the center is at the point (h, k) and the radius is "r".

So, given the equation of the circle:

x^2+y^2=12

You can identify that:

r^2=12

Then, solving for "r", you get that the radius of this circle is:

r=\sqrt{12}\\\\r=2\sqrt{3}

7 0
3 years ago
Read 2 more answers
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