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Sauron [17]
4 years ago
14

Which equation would you use to find how high the bird is flying?

Mathematics
1 answer:
damaskus [11]4 years ago
6 0

Answer:

The first one

Step-by-step explanation:

An easy way is SOH CAH TOA

SOH is that you use sine if you there is the opposite (in this case the question mark) and hypotenuse (the diagonal line)

CAH is that you use cosine for the adjacent side (1100) and the hypotenuse.

TOA is using tangent for the opposite and adjacent side.

To fine the question mark, you would use tangent. And plug in the given (1100 for the adjacent). So tan45 = x/1100.

If you need more help or clarification, let me know!

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22.6% of 65 is 14.69


65×22.6/100=14.69

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What is the estimate of 3630?
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The estimate of 3630 is 4000. because the hundreds place is higher than 5, so you would go a number higher
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Adele is 5 years older than Timothy. In three years, Timothy will be 2/3 of Adele’s age. What is Adele’s current age?
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A rectangular box with a volume of 684 ftcubed is to be constructed with a square base and top. The cost per square foot for the
SCORPION-xisa [38]

Answer:

The dimensions of the rectangular box is 36.23 ft×36.23 ft×4.345 ft.  

Minimum cost=2046.16 cents      

Step-by-step explanation:

Given that a rectangular box with a volume of 684 ft³.

The base and the top of the rectangular box is square in shape

Let the length and width of the rectangular box be x.

[since the base is square in shape,  length=width]

and the height of the rectangular box be h.

The volume of rectangular box is = Length ×width × height

                                                      =(x²h) ft³

x^2h=684\Rightarrow h=\frac{684}{x^2}  (1)

The area of the base and top of rectangular box is = x² ft²

The surface area of the sides= 2(length+width) height

                                               =2(x+x)h

                                               =4xh ft²

The total cost to construct the rectangular box is

=[(x²×20)+(x²×15)+(4xh×1.5)] cents  

=(20x²+15x²+6xh) cents

=(25x²+6xh) cents

Total cost= C(x).

C(x) is in cents.

∴C(x)=25x²+6xh

Putting h=\frac{684}{x^2}

C(x)=25x^2+6x\times\frac{684}{x^2} \Rightarrow C(x)=25x^2+\frac{4104}{x}

Differentiating with respect to x

C'(x)=50x-\frac{4104}{x^2}

To find minimum cost, we set C'(x)=0

\therefore50x-\frac{4104}{x^2}=0\\\Rightarrow50x=\frac{4104}{x^2}\\\Rightarrow x^3=\frac{4104}{50}\Rightarrow x\approx 4.345 ft.

Putting the value x in equation (1) we get

h=\frac{684}{(4.345)^2}

 ≈36.23 ft.

The dimensions of the rectangular box is 36.23 ft×36.23 ft×4.345 ft.  

Minimum cost C(x)=[25(4.345)²+10(4.345)(36.23)] cents

                               =2046.16 cents      

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3 years ago
-5/4 multiply by 1/3
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The answer to this problem is 5/12.

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