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sveticcg [70]
4 years ago
8

Write a compound inequality to represent all of the numbers between -4 and 6. PLEASE help

Mathematics
2 answers:
zvonat [6]4 years ago
8 0

Answer:

The compound inequality to represent all numbers between -4 and 6 is,

represented by the set  A = {x| -4 ≤ x ≤ 6}

Step-by-step explanation:

The compound inequality to represent all numbers between -4 and 6 is,

represented by the set  A = {x| -4 ≤ x ≤ 6}.

The above inequality is compound since it involves 2 '≤'  symbol.

kaheart [24]4 years ago
6 0

Answer:

A compound inequality is when it has two inequality sings. This is used to represent intervals, a set of number between two limits. In this case, we need to represent a set of numbers between -4 and 6. It's important to consider that "between" means that -4 and 6 are not included, so we want to represent all numbers more than -4 and less than 6.

So, the first part<em> "all numbers more than -4" </em>can be represented in two ways: x > -4 or -4 < x, both ways represents the same thing, but in this case we are gonna use -4 < x, because it's a compound inequality, where the "x" is always in the middle.

On the other hand, we have <em>"less than 6"</em>, this can be also represented in two ways: x < 6 or 6 > x. Now, we need to use the first expression, because to form the compound inequality we need the right side limit.

<h3>Therefore, the final compound inequality would be:</h3>

-4 < x < 6

Just remember, a compound inequality has a right side limit, and a left side limit. So, in this case the expression is saying considering all numbers between -4 and 6.

Now, we just need to apply an operator that indicates that the compound inequality is for all numbers between those limits. That universal operator is \forall.

<h3>At last, the final expression would be:</h3>

\forall x:-4 < x < 6.

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Rewrite the expression below.<br><br> -2a( a + b - 5)+ 3 (-5a + 2b) +b (6a + b - 8)
Paul [167]

Answer:

b^2 + 4 a b - 2 b - 2 a^2 + -5 a

Step-by-step explanation:

Simplify the following:

-2 a (a + b - 5) + 3 (2 b - 5 a) + b (6 a + b - 8)

-2 a (-5 + a + b) = 10 a - 2 a^2 - 2 a b:

10 a - 2 a^2 - 2 a b + 3 (2 b - 5 a) + b (6 a + b - 8)

3 (2 b - 5 a) = 6 b - 15 a:

10 a - 2 a^2 - 2 a b + 6 b - 15 a + b (6 a + b - 8)

b (-8 + 6 a + b) = -8 b + 6 a b + b^2:

10 a - 2 a^2 - 2 a b - 15 a + 6 b + -8 b + 6 a b + b^2

Grouping like terms, 10 a - 2 a^2 - 2 a b - 15 a + 6 b - 8 b + 6 a b + b^2 = b^2 + (6 a b - 2 a b) + (6 b - 8 b) - 2 a^2 + (10 a - 15 a):

b^2 + (6 a b - 2 a b) + (6 b - 8 b) - 2 a^2 + (10 a - 15 a)

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b^2 + 4 a b + (6 b - 8 b) - 2 a^2 + (10 a - 15 a)

6 b - 8 b = -2 b:

b^2 + 4 a b + -2 b - 2 a^2 + (10 a - 15 a)

10 a - 15 a = -5 a:

Answer:  b^2 + 4 a b - 2 b - 2 a^2 + -5 a

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