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just olya [345]
2 years ago
10

Hellppppppp:))))) Meee

Mathematics
1 answer:
Fiesta28 [93]2 years ago
4 0

it's a black screen can't see the question

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In the diagram, point o is the center of the circle
OLEGan [10]

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<em>There</em><em> </em><em>is</em><em> </em><em>no</em><em> </em><em>atta</em><em>chment</em><em> </em><em>showing</em><em> </em><em>a</em><em> </em><em>diag</em><em>ram</em><em>,</em><em> </em><em>so</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>to</em><em> </em><em>you</em><em>r question</em><em> is</em><em> </em><em>unk</em><em>nown</em><em>.</em>

4 0
3 years ago
 Evaluate the polynomial function p (x) = 2x4 - 3x2 + x - 1 to find p (-1).
Alisiya [41]
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7 0
3 years ago
I need help please and thank you
myrzilka [38]

Answer:

3

Step-by-step explanation:

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= 4 - (-2) / 3 -1

= 4+2/ 2

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4 0
3 years ago
Increase 100kg by 10%
Assoli18 [71]

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110kg

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8 0
3 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
2 years ago
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