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2 years ago

Hellppppppp:))))) Meee

Mathematics

1 answer:

Fiesta28 [93]2 years ago

4 0

it's a black screen can't see the question

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In the diagram, point o is the center of the circle

OLEGan [10]

Answer:

There is no attachment showing a diagram, so the answer to your question is unknown.

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3 years ago

Evaluate the polynomial function p (x) = 2x4 - 3x2 + x - 1 to find p (-1).

Alisiya [41]

$p(x)=2x^4-3x^2+x-1\\\\
Substitude\ p=-1\ into\ equation\\\\
p(-1)=2x^4-3x^2+x-1=2*(-1)^4-3(-1)^2-1-1=\\2*1-3*1-2=2-3-2=-3\\Answer\ p(-1)=-3$

7 0

3 years ago

I need help please and thank you

myrzilka [38]

Answer:

Step-by-step explanation:

Slope = y2- y1/ x2- x1

= 4 - (-2) / 3 -1

= 4+2/ 2

=6/2 = 3

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3 years ago

Increase 100kg by 10%

Assoli18 [71]

Answer:

110kg

Step-by-step explanation:

You multiply 100 by 0.1 (because this is 10% as a decimal number) and you get 10. Add 10 to 100

8 0

3 years ago

Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m

GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

$d=\sqrt{\frac{3h}{2} }$

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

$d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)$

For Addison h=85(1/3)

$d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)$

Subtracting both distances we get

$8\sqrt{2}-6\sqrt{2} =2\sqrt{2}$

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0

2 years ago