Question

line AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to line AB ?

Answer 1

Since the line is parallel to AB, the two slopes are the same
        
                      slope of AB = m = (y₂-y₁)/(x₂-x₁)
                                     
                                           m= (5-0)/(-6-(-3))= - 5/3
The equation of the line is y-y₁=m(x-x₁)
                      The origin    P(0,0) 
                                       y=mx
                                       y= -$\frac{5}{3}$x   Solution

Answer 2

The bottom answer is correct, just in case anyone is confused it would be

C. -5x-3y=0 which is the same thing as y= -5/3x + 0.