Answer:
Step-by-step explanation:
On the right side of the = multiply -4 through
add 28a and add 4 to both sides
divide both sides by 22
The wall area is the product of the room perimeter and the room height:
A₁ = (2*(12.5 ft + 10.5 ft))*(8.0 ft) = 368 ft²
The window and door area together is
A₂ = 2*((4 ft)*(3 ft)) + (7 ft)*(3 ft) = 45 ft²
The area of one roll of wallpaper is
A₃ = (2.5 ft)*(30 ft) = 75 ft²
Then the number of rolls of wallpaper required will be
1.1*(A₁ - A₂)/A₃ ≈ 4.74
5 rolls of wallpaper should be purchased.
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As a practical matter, not much of the window and door area can be saved. The rolls are 30 inches wide, but the openings are 36 inches wide. Some will likely have to be cut from two strips. The strips will have to be the full length of the wall, and the amount cut likely cannot be used elsewhere. If the window and door area cannot be salvaged, then likely ceiling(5.4) = 6 rolls will be needed (still allowing 10% for matching and waste).
There is 273 thousands. Remember, take out your zeros. Hope it helps! :)
Answer:
2 different perimeters, 32 cm and 40 cm
Step-by-step explanation:
Given the area of a rectangle is 64 cm squared.
We know, Area of the rectangle is = length x breath
∴ 64 = 8 x 8
Hence the sides can be 8 cm by 8 cm.
So the perimeter of the rectangle is = 8 cm + 8 cm + 8 cm +8 cm
= 32 cm
Also, Area of the rectangle is = length x breath
∴ 64 = 16 x 4
So the perimeter of the rectangle is = 16 cm + 4 cm + 16 cm +4 cm
= 40 cm