We can do this easily using 0s.
(x - i) (x + i) (x + 4) (x - 1) = 0
If you plug in any of the numbers, you'll get 0, making the equation true.
Answer:
8
Step-by-step explanation:
4(x)
4(2)
8
Answer:
-6-b
Step-by-step explanation:
4(1-2b)+7b-10
Multiply what's in parantheses
4(1)=4
4(-2b)=-8b
4-8b+7b-10
Combine like terms
4-10 -8b+7b
-6-b
Hope this helps :)
The formula of an area of a square:
![A=a^2](https://tex.z-dn.net/?f=A%3Da%5E2)
a - a side
We have ![A=450\ in^2](https://tex.z-dn.net/?f=A%3D450%5C%20in%5E2)
substitute:
![a^2=450\to a=\sqrt{450}\\\\a=\sqrt{225\cdot2}\\\\a=\sqrt{225}\cdot\sqrt2\\\\\boxed{a=15\sqrt2\ in}](https://tex.z-dn.net/?f=a%5E2%3D450%5Cto%20a%3D%5Csqrt%7B450%7D%5C%5C%5C%5Ca%3D%5Csqrt%7B225%5Ccdot2%7D%5C%5C%5C%5Ca%3D%5Csqrt%7B225%7D%5Ccdot%5Csqrt2%5C%5C%5C%5C%5Cboxed%7Ba%3D15%5Csqrt2%5C%20in%7D)
Used:
![\sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}](https://tex.z-dn.net/?f=%5Csqrt%7Ba%5Ccdot%20b%7D%3D%5Csqrt%7Ba%7D%5Ccdot%5Csqrt%7Bb%7D)
2 because there are 4 numbers of edges and 4 vertices