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3 years ago

Math......... I need

Mathematics

1 answer:

o-na [289]3 years ago

8 0

Answer:

She had to had like 20 since (-17-3)= -20 right the question asked how much she had before, she had 20 if not 28, since the mother gave her another twenty but as a result, in the beginning, she had around 28 dollars in order to spend 17 on a book and 3 on a cupcake so she still had 8 dollars, and the 20, well the mother handed her 20.

(I hoped I made sense, and that I helped!:)

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List the first 10 multiples for each number 3,4,7

notka56 [123]

Answer:

Step-by-step explanation:

3- 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

4- 4, 8, 12, 16, 20, 24, 28, 32, 36, 40

7- 7, 14, 21, 28, 35, 42, 49, 56, 63, 70

HOPE IT HELPED

3 0

3 years ago

Read 2 more answers

What is the gcf of 108 and 132

Reptile [31]

I believe the GCF of those two is 12.

6 0

3 years ago

Mathematics with applications in the management, Natural, and Social Sciences Twelfth edition

Fiesta28 [93]

Answer: 2014

Step-by-step explanation:

LED: -25x + 6y = 20

CFL: 15x + 2y = 322

we need to find which year it was the same to know where LED lighting surpassed CFL lighting

-25x + 6y = 20

15x + 2y = 322 (-3)

-25x + 6y = 20

-70x = -946

x = 13.51

The nearest year would be 14 which is 2014

8 0

3 years ago

PLS HELP 15 POINTS

Semmy [17]

Answer:

2√21

Step-by-step explanation:

Diagonal =√(L²+W²+H²)

Diagonal =√(8²+4²+2²)=√(64+16+4)=√84=2√21

4 0

3 years ago

The probability that a new car battery functions for more than 10,000 miles is .8, the probability that it functions for more th

MAXImum [283]

Answer:

There is a 50% probability that its total life will exceed 20,000 miles.

Step-by-step explanation:

To solve this question, we use the following formula:

$P(A|B) = \frac{P(A \cap B)}{P(B)}$

In which P(A|B) is the probability of A happening, given that B has happened, $P(A \cap B)$ is the probability of A and B happening, and P(B) is the probability of B happening.

In this problem, we want:

The probability of the total life of the car battery exceeding 20,000 miles, given that it exceeded 10,000 miles.

$P(A \cap B)$ is the probability of exceeding 20,000 and 10,000 miles. It is the same as the probability of exceeding 20,000 miles(If it exceeded 20,000 miles, necessarily it will have exceeded 10,000 miles). So $P(A \cap B) = 0.4$

P(B) is the probability of exceeding 10,000 miles. So $P(B) = 0.8)$

$P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{0.4}{0.8} = 0.5$

There is a 50% probability that its total life will exceed 20,000 miles.

6 0

3 years ago