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Softa [21]
3 years ago
9

Solve 3x-18=2y and 5x-6y=6 by elimination PLEASE SHOW WORK !!!!

Mathematics
2 answers:
Leokris [45]3 years ago
8 0

Answer:

x= 6/5y+6/5

x= 2/3y+6

Step-by-step explanation:

3x-18=2y

Step 1: Add 18 to both sides.

3x−18+18=2y+18

3x=2y+18

Step 2: Divide both sides by 3.

3x/3= 2y+18/3

x= 2/3y+6

#2

5x−6y=6

Step 1: Add 6y to both sides.

5x−6y+6y=6+6y

5x=6y+6

Step 2: Divide both sides by 5.

5x/5= 6y+6/5

x= 6/5y+6/5



Naddik [55]3 years ago
8 0

Answer:

x =12 and y =9

Step-by-step explanation:

3x -18 = 2y or 3x -2y = 18

 5x-6y = 6

Using elimination method

In order  make coefficient of y in both equation same with different sign ,

we multiply equation 1 by -3 and adding the obtained to equation 2

               -3(3x-2y) = 18x-3

             -9x +6y = -54

              5x -6y =  6

           -----------------------

           -4x       =  -48

             x = \frac{-48}{-4} = 12

            on plugging the value of y in equation   (1) ,we get

              3(12) -18 = 2y

               36 -18 = 2y

                2y = 18

                y = 18/2  = 9

            x = 12 and y = 9

             

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