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3 years ago

What is the decimal expression of the fraction 1/20?

Mathematics

2 answers:

kykrilka [37]3 years ago

4 0

I think it is .05 but I am not 100% sure

denpristay [2]3 years ago

4 0

The fraction $\frac{1}{20}$ written as a decimal is 0.05.
You find this answer by dividing one by twenty. Remember, fractions are just another way to write a division problem.

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4 × (28 ÷ 7)2 = <br> HURRYYYYY

umka21 [38]

The answer is 32

hope this helps! :)

8 0

3 years ago

A surfboard has an original price of $259. It is on sale for 55% off the original price.

grin007 [14]

I'm not sure what answer you need for this question?
original price: 259
sale: 55% off
55%=0.55
so 259×0.55=142.45
142.45 is the 55% of the original price
259－142.45=116.55
116.55 is the price after sale.
hope this would help. (*^ω^*)/

5 0

3 years ago

Read 2 more answers

A local animal rescue organization receives an average of 0.55 rescue calls per hour. Use the Poisson distribution to find the p

andreyandreev [35.5K]

Answer:

B) 0.894

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

A local animal rescue organization receives an average of 0.55 rescue calls per hour.

This means that $\mu = 0.55$

Probability that during a randomly selected hour, the organization will receive fewer than two calls.

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.55}*(0.55)^{0}}{(0)!} = 0.577$

$P(X = 1) = \frac{e^{-0.55}*(0.55)^{1}}{(1)!} = 0.317$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.577 + 0.317 = 0.894$

5 0

3 years ago

Fifty-five percent of the members of the junior varsity swim team wear glasses. Of the team memebers who do not wear glasses, 30

GarryVolchara [31]

the probability that a randomly chosen member of the JV swim team does not wear glasses and is in the 10th grade is 14%.

Given, the members of the junior varsity swim team wear glasses is 55%.

And the members of junior varsity swim team who do not wear glasses and in 10th grade is 30%.

Let the total no. of members be x.

So, the members of the junior varsity swim team wear glasses (55%),will be

$0.55x$ .

The total number of members not wearing glasses, will be

$x - 0.55 x = 0.45 x$ .

Now, the no. of members not wearing glasses and in 10th grade will be,

$\frac{0.45x\times30}{100} =0.135x$

We know that the probability of an event E, P(E) will be,

$P(E)=\frac{No.\ of Favourable\ outcomes}{total \ no. \ of \ outcomes}$

So, the probability for no. of members not wearing glasses and in 10th grade will be,

$P(E)=\dfrac{0.135x}{x}$

$P(E)=0.135\\\\P(E)=13.5 \%$

Hence the nearest whole percent of probability is 14%.

For more details on probability follow the link:

brainly.com/question/795909

8 0

3 years ago

Ken grew 4/5 of an inch last year. Sang grew 3/8 of an inch. Who grew more and by how much?

bonufazy [111]

Ken grew .425 of an inch more than sang because 4/5 is .8 and 3/8 is .375 what you do is you take those two numbers and subtract the smaller one from the bigger one and you get .425 and ken had the bigger growth. plz rate me brainliest

7 0

3 years ago

Read 2 more answers