All categories

3 years ago

A lamp is 36 inches ABOUT how many centimeters tall is the lamp (one inch is about 2.5 centimeters)

Mathematics

1 answer:

Viktor [21]3 years ago

7 0

The lamp is about 90 cm. to get this answer you take 36 and multiply it by 2.5.

You might be interested in

Find a quadratic polynomial with integer coefficients which has x = 2/9, ± SQRT23/9 as its real zeros.

melomori [17]

Answer:

The quadratic polynomial with integer coefficients is $y = 81\cdot x^{2}-36\cdot x -19$ .

Step-by-step explanation:

Statement is incorrectly written. Correct form is described below:

<em>Find a quadratic polynomial with integer coefficients which has the following real zeros: </em> $x = \frac{2}{9}\pm \frac{\sqrt{23}}{9}$ <em>. </em>

Let be $r_{1} = \frac{2}{9}+\frac{\sqrt{23}}{9}$ and $r_{2} = \frac{2}{9}-\frac{\sqrt{23}}{9}$ roots of the quadratic function. By Algebra we know that:

$y = (x-r_{1})\cdot (x-r_{2}) = x^{2}-(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2}$ (1)

Then, the quadratic polynomial is:

$y = x^{2}-\frac{4}{9}\cdot x -\frac{19}{81}$

$y = 81\cdot x^{2}-36\cdot x -19$

The quadratic polynomial with integer coefficients is $y = 81\cdot x^{2}-36\cdot x -19$ .

5 0

3 years ago

An ice cream cone has a diameter of 3 inches.The distance from the top of the cone to the point at the bottom (height) is 5 inch

solong [7]

Answer:

11.781 cubic inches (round accordingly)

Step-by-step explanation:

The formula for the volume of a cone is:

$V=\frac{1}{3}\pi r^{2} h$

where r is the radius and h is the height.

For our ice cream cone:

d = 3 inches

r = 1.5 inches (the radius is half of the diameter)

h= 5 inches

So all we have to do is plug in our values and solve for the volume:

$\frac{1}{3}\pi (1.5)^{2}(5) = 11.781$

So our final answer is around 11.8 cubic inches.

3 0

3 years ago

Simplify the following surd expressions

olasank [31]

Answer:

<h2>see the answers ⤵️</h2>

Step-by-step explanation:

<h3>to understand the solving steps you need to know about</h3>

algebra
PEMDAS
redical

<h3>adding or subtracting with redical experience is nothing but algebraic addition or subtraction</h3><h3>let's solve:</h3>

$a)7 \sqrt{3} - 2 \sqrt{3} + \sqrt{3} - 3\sqrt{3} \\ 8 \sqrt{3} - 5 \sqrt{3} \\ 3 \sqrt{3}$

$b)5 \sqrt{7} + 4 \sqrt{7} - 8 \sqrt{7} \\ 9 \sqrt{7} - 8 \sqrt{7} \\ \sqrt{7}$

6 0

3 years ago

Read 2 more answers

QF Q7.) Use properties of logarithms to expand the logarithmic expression as much as possible. Evaluate logarithmic expressions

Softa [21]

Attached is the solution.
The following log properties are used:
$log(x^n) = nlog(x)$
$log(\frac{a}{b}) = log(a) - log(b) \\ \\ log(ab) = log(a) + log(b) \\ \\ log_9 (81) = 2 \rightarrow 9^2 = 81$