Answer:
<h2>an+1 = 2×7ⁿ</h2>
Step-by-step explanation:
98÷14
=7
686÷98
=7
4 802÷686
=7
33 614÷4 802
=7
Then the common ratio q for this sequence is 7
recursive formula : an+1 = q×an = ?
an= a1 × qⁿ⁻¹
=2×7ⁿ⁻¹
an+1 = q×an
= 7×(2×7ⁿ⁻¹)
= 2×7ⁿ
<span>
The product of -5 and -4 is 20
The square of the smaller number, -5, is 25.
The product, 20, is indeed 5 less than 25, the square of the smaller number.</span>
The determinant of a 2 x 2 matrix can be calculated as:
Product of non-diagonal elements subtracted from product of diagonal elements.
The diagonal elements in given matrix are 12 and 2. The non-diagonal elements are -6 and 0.
So,
Determinant G = 12(2) - (-6)(0)
Determinant G = 24 - 0 = 24
So, option B gives the correct answer
There are two real roots (5 and -5) and 4 imaginary roots
