When we do this, the base of the parallelogram has length b 1 + b 2, and the height is the same as the trapezoids, so the area of the parallelogram is (b 1 + b 2)*h. Since the two trapezoids of the same size created this parallelogram, the area of one of those trapezoids is one half the area of the parallelogram
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1:SPLIT THE MID FACTOR
<span>X^2+8X+12
</span><span> X^2+6X +2X+12 [12=6*2
</span><span> 8=6+2
</span>
2:TAKE COMMON FACTORS FROM 1ST TWO AND <span>LAST TWO FACTORS
</span><span>X^2+6X +2X+12 EQUALS
</span><span>X(X+6) + 2(X+6)
</span>
<span>3: TAKE (X+6) AS COMMON FACTOR
</span><span> X(X+6)+2(X+6) EQUALS
</span><span>(X+6) {X+2}</span>
0 is the answer I got it doing the work
