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ANEK [815]
3 years ago
10

Mercury is the closest planet to the Sun, with an average distance of 35,000,000 miles. It takes light about 3 minutes to travel

from the Sun to Mercury.
Neptune is the farthest, with an average distance of 2.8 × 109 miles from the Sun.
How many times farther from the Sun is Neptune than Mercury? How long does it take light to reach Neptune? Follow the steps to find out.
1. Write the distance from the Sun to Mercury in scientific notation. Include units with your answer.

Write your answer in the space below.














2. Write and simplify an expression showing how many times farther Neptune is from the Sun than Mercury. Write the result in scientific notation.

Write your answer in the space below.














3. How many times longer does it take light from the Sun to reach Neptune than Mercury? Express this number in standard notation. Explain your reasoning.

Write your answer in the space below.














4. It takes light from the Sun about 3 minutes to reach Mercury. How many hours does it take light from the Sun to reach Neptune? Show your work.
Mathematics
2 answers:
GarryVolchara [31]3 years ago
8 0

Answer:

1) 3.5 x 10^7

2) 3.5 x 10^7/ 2.8 x 10^9 = 1.25 x 10^-2

I don't know number 3 or number 4. I am still trying to figure those out.

klemol [59]3 years ago
4 0

Sorry I'm too dumb to figure out the answer, I hope you find help soon.

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C. 6.2g can be combined with -3/8y. This is because they both end in ‘y’.
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p=number of seashells pierre collected

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Raghav has to load 2456 cartons of apples equally in 5 trucks. how many cartons will be left unloaded in the end?​
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12,280

Step-by-step explanation:

just do 1456×5 :))

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Each of the four sides of a swimming pool measures 9 meters. The pool is 5 meters deep. How much water will be needed to fill it
Alexxandr [17]

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D. 405

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3 years ago
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How do you do this question?
Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\

\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0
3 years ago
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