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Evgesh-ka [11]
3 years ago
13

What is the length of BC in the right triangle below

Mathematics
2 answers:
alex41 [277]3 years ago
8 0
The answer would be 15 units
Anna [14]3 years ago
6 0

Answer:

<h2><em>1</em><em>5</em><em> </em><em>units</em></h2>

<em>The </em><em>length </em><em>of </em><em>BC </em><em>is </em><em>1</em><em>5</em><em> </em><em>units.</em>

<em>Solution,</em>

<em>Hypotenuse(</em><em>h)</em><em>=</em><em>?</em>

<em>perpendicular(</em><em>p)</em><em>=</em><em>1</em><em>2</em>

<em>base(</em><em>b)</em><em>=</em><em>9</em>

<em>Using </em><em>Pythagoras</em><em> </em><em>theorem</em><em>,</em>

<em>{h}^{2}  =  {p}^{2}  +  {b}^{2}  \\ or \:  {h}^{2}  =  {12}^{2}  +  {9}^{2}  \\ or \:  {h}^{2}  = 12  \times 12 + 9  \times 9 \\ or \:  {h}^{2}  = 144 + 81 \\ or \:  {h}^{2}  = 225 \\ or \: h =  \sqrt{225}  \\ or \: h =  \sqrt{ {15}^{2} }  \\ h = 15</em>

<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>

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A discount book store sells hardcover books for $8 each and paperbacks for $4 each.The number of hardcover books, h, sold one da
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Jean-Paul's error is that he should have written the second equation as h = 4 p + 2.

<h3 />

<h3>How to solve an equation?</h3>

The hardcover book is $8 each and paperbacks for $4 each.

The number of hardcover books, h, sold one day was 2 more than four times the number of paperback books, p, sold that same day.

Therefore,

h = 4p + 2

Hence,

8h + 4p = 160

Therefore, the right equation are as follows:

h = 4p + 2

8h + 4p = 160

Hence, Jean-Paul should have written the second equation as h = 4 p + 2.

learn more on equation here: brainly.com/question/8465417

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2 years ago
Algebra 2 math. Can someone help me please?
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3 years ago
Given the polynomial 2x3 + 18x2 − 18x − 162, what is the value of the coefficient 'k' in the factored form?2x3 + 18x2 − 18x − 16
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Answer:

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Step-by-step explanation:

Let

f(x)=2x^3+18x^2-18x-162

We factor 2 to obtain;

f(x)=2(x^3+9x^2-9x-81)

We factor the polynomial within the parenthesis by grouping.

f(x)=2(x^2(x+9)-9(x+9)

f(x)=2(x^2-9)(x+9)

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We apply difference of two squares on the second factor: x^2-3^2=(x-3)(x+3)

f(x)=2(x+3)(x-3)(x+9)

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3 years ago
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3 years ago
Using the rule y = 2x + 3, find the value of y when x is 3.<br> A) 0 <br> B) 8 <br> C) 9 <br> D) 12
tia_tia [17]
Hi there.

Y = 2x + 3
Solve for y when x = 3
The first thing we need to do is replace x by the 3 in the equation.
Y = 2(3) + 3
Y = 6 + 3
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Thus, your answer is : C
7 0
3 years ago
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