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Vlada [557]
3 years ago
14

What are the Zeros of the quadratic function below?* 10 points

Mathematics
1 answer:
S_A_V [24]3 years ago
3 0
It says it’s 5 points not 10 points!
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50 points question!!!
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Answer:

The graph of f(x) has exactly two x-intercepts not true.

A straight line cannot intersect the x axis twice, so a graph should never have two x-intercepts.

Hope this helps!

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Round these decimals to 2 decimals places.Please I need some help...
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9×2=2×9 what is the property of this problem?​
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3 years ago
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Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

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\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

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\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
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