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ELEN [110]
2 years ago
10

​ A sample of n = 9 college students is used to evaluate the effectiveness of a new Study Skills Workshop. Each student’s grade

point average (GPA) is recorded for the semester before the workshop and for the semester after the workshop. The average GPA improved by MD = 0.60 points with s2 = 0.09. The researcher would like to use the sample to estimate how much effect the workshop would have for the entire college population. Which of the following is the 80% confidence interval for these data?
A) μD = 0.60 ± 0.09( 1.860)
B) μD = 0.60 ± 0.10(1.397)
C) μD = 0.60 ± 0.01(1.397)
D) μD = 0.60 ± 0.10( 1.860)
Mathematics
1 answer:
forsale [732]2 years ago
6 0

Answer:

B) μD = 0.60 ± 0.10(1.397)

Step-by-step explanation:

The confidence interval is given by:

MD±t_{\alpha/2, n-1} \frac{s}{\sqrt{n} }

Where

MD=60

n=9

df=n-1=8

t_{\alpha/2, n-1}=1.397

s=\sqrt{0.09} =0.3

Then the confidence interval is

μD=0.60±1.397*(0.3/√9)

μD=0.60±0.10*(1.397)

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To get an average, you must do the following steps.

step 1:add all the numbers together.
190258.50+152698.00+122753.00+220523.00+231951.00= 918183.5Step 2: divide the ANSWER you get by the amount of numbers there are:
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your answer is: 183636.7
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hope this helps :D
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