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4 years ago

The sumof a number and 48 is -18

Mathematics

2 answers:

ollegr [7]4 years ago

7 0

The answer is -66. Work shown below.

NNADVOKAT [17]4 years ago

6 0

⇒If the unknown x;

48 + x = -18

⇒Known unknowns to one side into the other side .

x = -18-48

x=-66

Have a nice days............

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Choose the equation below that represents the line that passes through the point (7, -2) and has a slope of -3

Norma-Jean [14]

Answer:

Option C

Step-by-step explanation:

All of these equation have a slope of x=-3, as this is the only number that will be acompanied by an x (the slope of a function is the number on the equation that has an X). To know which one of this equations passes through the points (7;-2) we can supplant these numbers on each equation until the result at both sides are equals.

The correct answer is the option c, because if we supplant these numbers (x=7 and y=-2) on the equation, we get an equality.

$y + 2 = -3. (x - 7) // -2 + 2 = -3. (7 - 7) //0 = 0$

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4 years ago

The function (t) = 1,000(1.06)2t models the value of an investment after tyears.

Natasha_Volkova [10]

Answer: B not sure if I’m right though .

Step-by-step explanation:

8 0

3 years ago

BRAINLIEST)

Sedbober [7]

1/4 + 2/3

= 3/12 + 8/12

=11/12

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7 0

3 years ago

Read 2 more answers

Please help me with this question

wlad13 [49]

Answer:

-3

Step-by-step explanation:

Remember the following:

cos(x)=cos(x/2 + x/2) = cos(x/2)*cos(x/2) -sin(x/2)*sin(x/2)

cos(x)=cos2(x/2) - sin2(x/2)

We also know that sin2(a)+cos2(a)=1,

so sin2(x/2)=1 - cos2(x/2). obtained from previous step.

So, our first expression can be written as:

cos(x)=cos2(x/2)-1+cos2(x/2)

Where we obtain that: cos(x/2)= sqrt( 1+ cos(x))/ sqrt(2)

If we again use sin2(a)+cos2(a)=1, we will obtain the following relation:

sin(x/2)= sqrt(1-cos(x))/sqrt(2)

Next Tang(x/2)= sin(x/2) / cos(x/2)= sqrt(1-cos(x))/sqrt(1+cos(x))=

SQRT(9/1)=3

In the given range, cos(x), hence tan(x/2) is also negative

6 0

3 years ago

An airplane pilot wants to climb from an altitude of 6000 feet to 16,000 feet. If the plane climbs at an angle of 9 degrees, wit

puteri [66]

So, the pilot goes from 6,000 to 16,000 or distance up of 10,000 feet
the plane is going at a speed of 22,000 per minute, namely, dx/dt = 22,000

so. .if you look at the picture below... we can simply use tangent
keeping in mind that, as the plane moves up and up, the angle is "constant", is never changing, whilst "y" and "x" and even "r" are changing, but we're not using "r" in this case.... we know what dx/dt is, we know the angle is a constant, this matters because the derivative of a constant is just 0

so, we really just need to find dy/dt then, because whilst dx/dt is telling us how fast is moving horizontally, dy/dt is telling us how long it took to cover those 10,000 feet

thus $\bf tan(\theta)=\cfrac{y}{x}\implies tan(\theta)=yx^{-1}\implies tan(9^o)=yx^{-1}\\\\
-----------------------------\\\\
0=\left( \cfrac{dy}{dt}\cdot \cfrac{1}{x} \right)+\left( y\cdot -\cfrac{1}{x^2}\cdot \cfrac{dx}{dt} \right)\implies 0=\cfrac{\frac{dy}{dt}}{x}-\cfrac{y\frac{dx}{dt}}{x^2}
\\\\\\
$

$\bf \\\\\\
\cfrac{y\frac{dx}{dt}}{x^2}=\cfrac{\frac{dy}{dt}}{x}\implies \cfrac{y\frac{dx}{dt}}{x}=\cfrac{dy}{dt}
\\\\\\
\textit{so, what's "x" when y = 10000?}
\\\\\\
tan(9^o)=\cfrac{10000}{x}\implies x=\cfrac{10000}{tan(9^o)}\implies x\approx 63175.5$

once you find what dy/dt is... you can simply do a quick conversion for the 10,000 feet, to see how many minutes it took

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3 years ago