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3 years ago

50 pts

English

1 answer:

natali 33 [55]3 years ago

8 0

D. It is the Authors attempt to use autobiographical incident to share valuable wisdom.

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Answer:

1. How can everything come from nothing when nothing is something that has nothing to do with anything?

2. Is everything nothing or nothing is everything?

3. Why nothing is nothing and everything is everything?

4. What if nothing is anything and everything is not everything?

5. What will you do when you do nothing?

6. Why am I so mad and asking all the questions that make no sense and makes sense to those only who have common sense?

7. Why do fish don’t get cold even after living their entire life in water?

8. How can “makes sense” make sense and “nonsense” make no sense?

9. If the Big Bang happened 14 billion years ago, when did the small bang happen?

10. If I am breathing while I'm sleeping, does that mean I will live after death?

Your answer is no.

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1 year ago

PLZ ANALYZE THIS POEM THE BEST YOU CAN. TY. WILL MARK BRAINLYIEST <3

pishuonlain [190]

Answer:

My soul is on fire

Because of desire,

Explanation:

cause it is explaining what he feels

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2 years ago

can someone help me with some annotations for the book "All The Light We Cannot See"? I only need to annotate 4 pages but I want

vodka [1.7K]

Plot Summary
Chapters
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3 years ago

Which of the following words best characterizes Mary Warren

Arada [10]

<span>Which of the following words best characterizes Mary Warren? gullible.</span>

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3 years ago

I will make you brainlist if you help me the 2 question by explain them i swear i will make you brainlist

Xelga [282]

★ Formula Applied :

$\begin{gathered}\sf \bullet\ \; cos^2x-sin^2x=cos2x\\\\\to\ \sf \pink{sin^2x-cos^2x=-cos2x}\end{gathered}$

$\begin{gathered}\bullet\ \; \sf sin2x=2.sinx.cosx\\\\\to \sf \blue{sinx.cosx=\dfrac{sin2x}{2}}\end{gathered}$

$\displaystyle \bullet\ \; \sf \int \dfrac{dx}{x}$

$\bullet\ \; \sf \ln (ab)=\ln a+\ln$

★ Explanation :

$\begin{gathered}\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}dx\\\\\to \sf \int \dfrac{-cos2x}{\frac{sin2x}{2}}dx\\\\\to \sf \int \dfrac{-2cos2x}{sin2x}dx\end{gathered}$

Lets use substitution method ,

Let , u = sin2x

⇒ du = 2.cos2x.dx

$\begin{gathered}\to \displaystyle \sf \int \dfrac{-du}{u}\\\\\to \sf -\int \dfrac{du}{u}\\\\\to \sf -ln|u|\\\\\end{gathered}$

$\to \sf \red{-ln|sin2x|+c}$

$\to \sf - \ln |2sinx.cosx|+c$

$\to \sf - \ln |sinx.cosx|+(\ln 2+c)$

$\leadsto - \sf \red{\ln |sinx.cosx|+c}\ \; \bigstar$

★ Alternate Method :

$\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}$

$\displaystyle \to \sf \int \left( \dfrac{sin^2x}{sinx.cosx}-\dfrac{cos^2x}{sinx.cosx}\right)dx$

$\begin{gathered}\displaystyle \to \sf \int \left( \dfrac{sinx}{cosx} -\dfrac{cosx}{sinx} \right)dx\\\\\to\ \sf \int (tanx-cotx)dx\\\\\to \sf \int tanx.dx-\int cotx.dx\\\\\to \sf ln|secx|-ln|sinx|+c\end{gathered}$

$\to \sf ln\left| \dfrac{secx}{sinx}\right|+c$

$\begin{gathered}\to \sf ln\left| \dfrac{1}{sinx.cosx} \right|+c\\\\\end{gathered}$ ]

$\leadsto \sf \pink{-ln|sinx.cosx|+c}\ \; \bigstar$

4 0

3 years ago