If F(a, b, c, d) = a^b + c \times d, what is the value of x such that F(2, x, 4, 11) = 300?
1 answer:
Answer:
x = 8
Step-by-step explanation:
A graphing calculator can show you the answer easily. It works well to define a function whose x-intercept is the solution. We can do that by subtracting 300 from the given equation so we have ...
F(2, x, 4, 11) -300 = 0
The solution is x = 8.
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We can solve this algebraically:
F(2, x, 4, 11) -300 = 0
2^x +4·11 -300 = 0 . . . . use the function definition
2^x -256 = 0 . . . . . . simplify
2^x = 2^8 . . . . . add 256
x = 8 . . . . . . . . . match exponents of the same base
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Answer:
Step-by-step explanation:
Answer:
The Loan amount at 11 % interest rate is $ 18,500 And
The Loan amount at 9 % interest rate is $ 19,000
Step-by-step explanation:
Given as :
Let The loan given at interest rate of 11 % annual = $ x
And The loan given at interest rate of 9 % annual = ($37,500 - $ x)
Total interest fro both loan = $3745
I.e CI 1 + CI 2 = $3745
Now, From compound interest method :
Or, A 1 = $ 1.11 x
<u>Similarly</u>
Or, A 2 = 1.09 × ($37,500 - $ x)
∵ Compound Interest = Amount - principal
Or, $ 3745 = CI 1 + CI 2
Or, $ 3745 = ($ 1.11 x - $ x) + ( 1.09 × ($37,500 - $ x) - ($37,500 - $ x) )
Or, $ 3745 = $ .11 x+ ($37,500 - $ x) ( .09 )
Or, $ 3745 = $ .02 x + $ 3375
or, 0.02 x = $ 3745 - $ 3375
∴ x = $
SO, x = $ 18,500
And $ 37500 - x = $ 19,000
Hence The Loan amount at 11 % interest rate is $ 18,500 And
The Loan amount at 9 % interest rate is $ 19,000 Answer