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2 years ago

When multiplying or dividing a NEGATIVE and a POSITIVE, your answer will be... (if you spell it wrong, it will mark

Mathematics

2 answers:

serg [7]2 years ago

8 0

Answer:

Both are negative

Step-by-step explanation:

If multiplying= It will always be negative

If dividing= It will also always be negative

professor190 [17]2 years ago

8 0

Answer:

There are two simple rules to remember: When you multiply a negative number by a positive number then the product is always negative. When you multiply two negative numbers or two positive numbers then the product is always positive.

When dividing negatives and positive number be sure to court the signs. If there are two negatives then they will cancel each other out, so if you have an even number (or zero) of negative signs then the answer will be positive

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8 < 4(x+1) show your work

kati45 [8]

8 < 4 (x + 1) Use the Distributive Property
8 < 4x + 4 Subtract 4 from both sides
4 < 4x Divide both sides by 4
1 < x

5 0

2 years ago

Find tsa of cylinder whose height is 7cm and radios 4cm.

ki77a [65]

Answer:

Answer

Let height =h

Total surface area=2πr(r+h)

r=7cm

⇒968=2×

×7(7+h)

⇒

968

=7+h

⇒h+7=22

⇒h=22−7

=15cm.

Step-by-step explanation:

6 0

2 years ago

You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu

aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to $180^{o}$ .

Let the exterior angle be represented by $x^{o}$ , and the three interior angles of the triangle be represented by $a^{o}$ , $b^{o}$ and $c^{o}$ .

Assume that the vertex angle $c^{o}$ is the linear pair to the exterior angle $x^{o}$ .

i.e $x^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles on a straight line)

Thus,

i. $a^{o}$ + $b^{o}$ = $x^{o}$ (sum of two opposite interior angles is equal to an exterior angle)

⇒ $a^{o}$ = $x^{o}$ - $b^{o}$

Also,

$b^{o}$ = $x^{o}$ - $a^{o}$

But,

$a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

⇒ $c^{o}$ = $180^{o}$ - ( $a^{o}$ + $b^{o}$ )

and

$a^{o}$ + $b^{o}$ = $180^{o}$ - $c^{o}$

ii. $a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

$a^{o}$ = $180^{o}$ - ( $b^{o}$ + $c^{o}$ )

Also,

$a^{o}$ + $b^{o}$ = $x^{o}$

⇒ $b^{o}$ = $x^{o}$ - $a^{o}$

$c^{o}$ = $180^{o}$ - $x^{o}$

8 0

2 years ago

How would I solve y-8+3(y+4)

konstantin123 [22]

Answer:

y-8+3y+12

4y+4

Step-by-step explanation:

y-8+3y+12

4y+4 is your answer

6 0

3 years ago

0.006/6,000 is it Much Larger than or close to 1

ANEK [815]

Answer:

Less close to one

Step-by-step explanation:

0.006/6,000= 0,000001

7 0

2 years ago