Multiply the constants. Multiply the variables according to the rules of exponents.
$(-2q^{4})(-8q^{3}b^{6}) = ((-2)(-8))q^{(4+3)}b^{6}\\\\=16q^{7}b^6}$

4 0

3 years ago

Given a line with a slope of1/2 and a point(6,5) which lies on that find an equation to represent that line

kondor19780726 [428]

Answer:

The equation of the line is given as 2 y - x = 4.

Step-by-step explanation:

Here, the slope of the given line = 1/2

The point on the line is (x0,y0) = (6,5)

Now, by POINT SLOPE FORMULA:

The equation of line with (x0,y0) and slope m is written as:

(y - y0) = m (x-x0)

So, here the equation of line is given as

$( y- 5) = \frac{1}{2} (x-6)\\\implies 2( y-5) = ( x-6)\\or, 2y - 10 = x - 6\\\implies 2y - x = 4$

Hence the equation of the line is 2 y - x = 4.

8 0

3 years ago

A cruise ship is currently 20 kilometers away from its port and is traveling away from the port at 5 kilometers per hour . The f

Paladinen [302]

Answer:

The ship will be $37.5\ km$ far from its port 3.5 hours from now

Step-by-step explanation:

The function is $y=5x +20$ relates the number of kilometers y the ship will be from its port x hours from now, it has a form $y=vt+y_{0} \ where \ y\ is\ final\ distance\\v\ is\ velocity\ in\ km/h,\ t\ is\ time\\and\ y_{0}\ is\ initial\ distance$ .

As the function is clearly defined, we only have to evaluate it for $x=3.5$ , so $y(3.5)=5(3.5)+20=17.5+20=37.5 \ km$ is the distance between the cruise ship and its port after 3.5 hours.

7 0

2 years ago