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3 years ago

What is the area of the semicircle in square feet (use 3.14 for π.) helpp due in 21 minutes

Mathematics

1 answer:

Elden [556K]3 years ago

7 0

Answer:

14.13

Step-by-step explanation:

use the radius, 3 squared

so 3 x 3 = 9

9 x 3.14 = 28.26

28.26 / 2 ( because it is a semicircle) = 14.13

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There are 3 red chips and 2 blue chips. If they form a certain color pattern when arranged in a row, for example RBRRB, how many

svp [43]

Answer:

Option A - 10

Step-by-step explanation:

Given : There are 3 red chips and 2 blue chips. If they form a certain color pattern when arranged in a row, for example RBRRB.

To find : How many color patterns are possible?

Solution :

Total number of chips = 5

So, 5 chips can be arranged in 5! ways.

There are 3 red chips and 2 blue chips.

So, choosing 3 red chips in 3! ways

and choosing 2 blue chips in 2! ways.

As changing the places of similar chip will not create new pattern.

The total pattern is given by,

$T=\frac{5!}{3!\times 2!}$

$T=\frac{5\times 4\times 3!}{3!\times 2}$

$T=10$

Therefore, color patterns are possible are 10.

Option A is correct.

4 0

3 years ago

Grehyesjeyehevshsh. *Cries in no knowledge*

PilotLPTM [1.2K]

Answer:

GIRL ITS M!!!!!!

Step-by-step explanation:

its the furthest to the right on the number line

6 0

2 years ago

Write the first 4 multiples of 3/8

sesenic [268]

Multiples of 3

: 3, 6, 9, 12, 15, 18, 21, 24, ...

Multiples of 4

: 4, 8, 12, 16, 20, 24, ...

Multiples of 8

: 8, 16, 24, ..

Find the smallest number that is shared by all rows above. This is the LCM.

LCM = 2424

Method 2: By Prime Factors

List the prime factors of each number.

Prime Factors of 3

: 3

Prime Factors of 4

: 2, 2

Prime Factors of 8

: 2, 2, 2

Find the union of these primes.

2,2,2,32,2,2,3

Multiply these numbers: 2\times 2\times 2\times 3=242×2×2×3=24. This is the LCM.

LCM = 2424

3 0

3 years ago

A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between

sattari [20]

Answer:

$B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)$

b) 0.09

Step-by-step explanation:

We are given the following in the question:

$B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)$

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

$B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)$

b) rate of increase after one day.

We put t = 1

$B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(1) = \dfrac{0.9\pi}{4.4}\bigg(\cos(\dfrac{2\pi (1)}{4.4}\bigg)\\\\B'(t) = 0.09145\\B'(t) \approx 0.09$