Answer:
3
Step-by-step explanation:
note that zeros and x-intercepts are the same with different names
There are 2 zeros from the quadratic factor and 1 from the linear factor.
To find them equate the function to zero, that is
(x² - x - 2)(3x - 2) = 0
(x - 2)(x + 1)(3x-2) = 0 ← factoring the quadratic
equate each factor to zero and solve for x
x - 2 = 0 ⇒ x = 2
x + 1 = 0 ⇒ x = - 1
3x - 2 = 0 ⇒ x =
If they don't intersect then there is no solution and the lines are parrell.
For the first question, use slip and slide or the box method to get (x-2)(2x-3)
Do the same for the second question to get (3x-4)(x+1)
Answer:
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Step-by-step explanation:
hmmmmmmmmmmmm
Step-by-step explanation:
-1<x<infinity this is answer I guess