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mrs_skeptik [129]
3 years ago
5

Which test point holds true for 3/2y - 2x>1?

Mathematics
1 answer:
ANTONII [103]3 years ago
7 0
There exists a question that instead of >, the symbol used is ≥. Substitute the value of abscissas and ordinates of the points to x and y, respectively.

A. (1/4, 1)      (3/2)(1) - 2(1/4) = 1              TRUE
B. (4, 1)         (3/2)(1) - 2(4) = -6.5             FALSE
C. (1, 1/4)      (3/2)(1/4) - 2(1) = -1.625      FALSE
D. (1, 0)         (3/2)(0) - (2)(1) = -2              FALSE
E (1/4, 3/4)    (3/2)(3/4) - (2)(1/4) = 0.625  FALSE

Thus, the answer is letter A. 

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Answer:

3.13

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

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We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

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Chi square critical value for lower tail =

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80% confidence interval:

\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}

Putting values, we get,

=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

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