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belka [17]
3 years ago
12

Choose the situation in which the use of exact number is most appropriate.

Mathematics
1 answer:
Lelu [443]3 years ago
7 0
Ordering laptops. Much more expensive. Higher consequences. 
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Find the value of x that makes the equation true<br> 3 ( x- 8 ) + 2x = 76
vovikov84 [41]

Answer:

x = 20

Step-by-step explanation:

3 (x-8) +2x = 76

3x - 24 +2x = 76

3x+2x = 76+24

5x = 100

x = 20

7 0
3 years ago
Need help please!!!!!!
zlopas [31]
The distance from a to c is ten units
8 0
3 years ago
What score does jane need to receive an 85% average if she has an 32,90,92,82,64
topjm [15]
(32 + 90 + 92 + 82 + 64 + x) / 6 = 85
(360 + x) / 6 = 85
360 + x = 85 * 6
360 + x = 510
x = 510 - 360
x = 150 <===
5 0
3 years ago
Read 2 more answers
M is the midpoint of A and B. Find the A (Leave your answer with no spaces and use brackets and commas, use M and B as examples.
Licemer1 [7]

Answer:

<h2>A = (1,-5)</h2>

Step-by-step explanation:

Let the midpoint of the two points A (x₁, y₁) and B(-5, 5) be M(2, 0)

Using the formula for calculating the midpoints of two coordinates

(X₁, Y₁) = (\frac{{x_1}+x_2}{2}, \frac{{y_1}+y_2}{2} )

X_1 = \frac{{x_1}+x_2}{2}\\Y_1 =\frac{{y_1}+y_2}{2}

Given if (X₁, Y₁) is the midpoint, then X₁ = 2, Y₁ = 0

x₂ = -5 and y₂ = 5

Substituting this given values into the equation above to get the unknown coordinate;

X_1 = \frac{{x_1}+x_2}{2}\\-2 =  \frac{{x_1}-5\\}{2}\\-4 = x_1-5\\x_1=-4+5\\x_1 =1

Similarly;

Y_1 = \frac{{y_1}+y_2}{2}\\0 =  \frac{{y_1}+5\\}{2}\\0 = y_1+5\\y_1=0-5\\y_1 =-5

The coordinate of A = (1,-5)

5 0
3 years ago
Factor completely. . 8x^3-27. Show solution with explanation.
Kitty [74]
Here we are given 
<span>8x^3-27
now making both as a cube root
</span><span>(2x)^3-(3)^3 
using formula cube root
</span><span> a^3-b^3=(a-b)(a^2+ab+b^2)
</span>where 
a=2x
b=3
now putting these values 
<span>2x^3-3^3=(2x-3)(2x^2+2x*3+3^2)
simplifying
</span>2x^3-3^3=<span>(2x-3)(4x^2+6x+9)
</span>hence the right answer is 
2x^3-3^3=<span>(2x-3)(4x^2+6x+9)</span>
7 0
3 years ago
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