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3 years ago

12

PLZ ANSWER THIS ITS DUE TODAY I WILL GIVE BRAINLEST!!!!

2 answers:

fgiga [73]3 years ago

5 0

The person above me Is right

Sever21 [200]3 years ago

3 0

Answer:

In many instances, the lyrics to folk songs came from existing nursery rhymes or poems, and some of the nursery rhymes had variations, depending on region or time. Thus, these folk songs may have lyrics that are slightly different from those you are familiar with.

Therefore, in my opinion, I think that Nursery songs can be considered folk music.

Im so so so so sorry if this is wrong or not the answer you were looking for. i truly am. hopefully this will be good

Step-by-step explanation:

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Line A is represented by the following equation:

Vesnalui [34]

- for line B so the set of equations to have no solutions bc. x+y=2 and so y=2-x
so from x+y=4 will result y=4-x

so this is the right equation for line B so the set of equations has no solutions

6 0

3 years ago

Read 2 more answers

Need help please and thank

cupoosta [38]

Answer:

The Answer is B

Step-by-step explanation:

All the numbers and coefficients in option B correspond with the ones in the question. Hope this helps :)

7 0

3 years ago

Given that S is the centroid of triangle MNO, find SQ.

AnnZ [28]

Answer:

|SQ|=5

Step-by-step explanation:

If S is the median, then OP is a median of triangle OMN.

This implies that:

|MP|=|NP|

$3x-4=x+4$

We group like terms and solve for x.

$3x-x=4+4$

$\implies 2x=8$

$\implies x=4$

Now we know that: MN:SQ=2:1

But MN=2x+2

This implies that:

2x+2:SQ=2:1

Put x=4

2(4)+2:SQ=2:1

10:SQ=2:1

Therefore |SQ|=5

7 0

3 years ago

Subtract -7x + 6 from -2x^2 + 9x - 2

JulsSmile [24]

Answer:

$( - 2 {x}^{2} + 9x - 2) - ( - 7x + 6) \\ = - 2 {x}^{2} + (9 + 7)x + ( - 2 - 6) \\ = - 2 {x}^{2} + 16x - 8$

4 0

3 years ago

Let f(x) = cx^k be a power function such that f(13) is four times the size of f(1). What is the power k?

Ivenika [448]

Answer:

0.540

Step-by-step explanation:

Hi there,

To get started in order to solve this, please recall the property of logarithms.

This question is a bit tricky, but doable. Best way to solve this is first compare the two functions:

$f(x) = cx^{k} \\ f(13)=4f(1)$

Now, let's see what the function gives at 13 and 1:

$f(13)=c13^{k}\\f(1)=c1^{k}$

Something to recognize is that 1 to the power of <em>anything</em> is just 1, so f(1) is reduced to:

$f(1)=c$ We are making progress!

Next, we can set both f(13) forms equivalent to each other, watch this:

$f(13)=f(13) = 4f(1)$ but we know what f(1) is equal to, and let's substitute our knowns:

$c13^{k}=4c1^{k} = 4c$ the c constant on both left and right side cancel out:

$13^{k}=4$ Now, take the logarithm form of both side of the equation. I used natural log, but you can also use common logs:

$ln(13^{k})=ln(4)$ ⇒ $k*ln(13)=ln(4)$ this was performed using <em>the power log rule. </em>

Isolate k:

$k=\frac{ln(4)}{ln(13)} =0.540$ using a calculator.

If you liked this solution, hit Thanks or give a rating!

thanks,

8 0

3 years ago