Solve the given equation.<br><br> g/5 = 10

Write the standard equation of a circle with center (-9,-4) and radius 15.

Oksi-84 [34.3K]

Answer:

Equation of a circle:

radius = the sq. rt of (x - h)^2 + (y - k)^2

Plug in the values for the center of a circle and the radius:

15 = the sq. rt of (x + 9)^2 + (y + 4)^2

(x + 9)^2 + (y + 4)^2 = 225

The answer is A or the first one.

5 0

3 years ago

What is the effect on the graph of the function f(x) = x^2 when f(x) is changed to f(x − 6)

olya-2409 [2.1K]

Answer:

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing $f(x) = x^2$ and $\:f\left(x\right)=\left(x-6\right)^2$ is represented as being shifted 6 units to the right as compare to the function $f(x) = x^2$ .

Step-by-step explanation:

When we Add or subtract a positive constant, let say c, to input x, it would be a horizontal shift.

For example:

Type of change Effect on y = f(x)

$y = f(x - c)$ horizontal shift: c units to right

So

Considering the function

$f(x) = x^2$

The graph is shown below. The first figure is representing $f(x) = x^2$ .

Now, considering the function

$\:f\left(x\right)=\left(x-6\right)^2$

According to the rule, as we have discussed above, as a positive constant 6 is added to the input, so there is a horizontal shift, 6 units to the right.

The graph of $\:f\left(x-6\right)=\left(x-6\right)^2$ is shown below in second figure. It is clear that the graph of $\:f\left(x-6\right)=\left(x-6\right)^2$ is shifted 6 units to the right as compare to the function $f(x) = x^2$ .

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing $f(x) = x^2$ and $\:f\left(x\right)=\left(x-6\right)^2$ is represented as being shifted 6 units to the right as compare to the function $f(x) = x^2$ .

5 0

3 years ago

What is the square root of 396?

hjlf

19.899 as an approximation
2 sqrt (99) = 6sqrt (11) exactly

6 0

4 years ago

Read 2 more answers

Plsss help!!

vivado [14]

16 students from year 10 have cooked lunches

6 0

3 years ago

Read 2 more answers

Please help me solve this short problem guys

-BARSIC- [3]

Answer:

Step-by-step explanation:

Given equation of the quadratic function is,

y = x² + 5x - 7

Convert this equation into vertex form,

y = x² + 2(2.5x) - 7

= x² + 2(2.5x) + (2.5)² - (2.5)² - 7

= (x + 2.5)²- 6.25 - 7

= (x + 2.5)² - 13.25

Therefore, vertex of the function is → (-2.5, -13.25)

For the solutions,

y = 0

(x + 2.5)² - 13.25 = 0

x = (±√13.25) - 2.5

x = (±3.64) - 2.5

x = 1.14, -6.14

Solutions → (-6.14, 0) and (1.14, 0)

8 0

3 years ago

Solve the given equation. g/5 = 10