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rewona [7]
3 years ago
8

I'll Mark you brainliest!! I will report answers if you answer for points. Period.

Mathematics
2 answers:
Karolina [17]3 years ago
6 0

a SAS congruence postulate means that it must have an equal side,angle,side! so in this example, it tells us a side that's equal so you'd need to prove an angle and another side to prove the triangles congruent. I lost my notes on how to solve it sorry.

RoseWind [281]3 years ago
4 0

Answer:

AC is perpendicular to BD.

Step-by-step explanation:

We observe that both the ABC triangle and the ADC triangle have the same AC side length. Therefore we know that  is reflexive.

The length of the base of the triangle is the same, i.e., .

In order to prove the triangles congruent using the SAS congruence postulate, we need the other information, namely . Thus we get ∠ACB = ∠ACD = 90°.

Conclusions for the SAS Congruent Postulate from this problem:  

∠ACB = ∠ACD  

- - - - - - -  - -  

The following is not other or additional information along with the reasons.  

∠CBA = ∠CDA no, because that is AAS with ∠ACB = ∠ACD and  

∠BAC = ∠DAC no, because that is ASA with  and ∠ACB = ∠ACD.

No, because already marked.

- - - - - - - - - -

Notes:  

The SAS (Side-Angle-Side) postulate for the congruent triangles: two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle; the included angle properly represents the angle formed by two sides.

The ASA (Angle-Side-Angle) postulate for the congruent triangles: two angles and the included side of one triangle are congruent to two angles and the included side of another triangle; the included side properly represents the side between the vertices of the two angles.  

The SSS (Side-Side-Side) postulate for the congruent triangles: all three sides in one triangle are congruent to the corresponding sides within the other.

The AAS (Angle-Angle-Side) postulate for the congruent triangles: two pairs of corresponding angles and a pair of opposite sides are equal in both triangles.  

---------------------------

Here's another way to solve it:

Given a triangle ABD.  C is the mid point of BD.

To prove that the two triangles are congruent we have to use SAS axiom.

Here consider two triangles ABC and ADC

Statement                        Reason

1) BC = CD                       D is the mid point of BD

2) AC = AC                       Reflexive property

Since we have two sides congruence we must have included angle congruence

i.e. Angle ACB = Angle ACD

If this information is given, then this completes the SAS congruence for the two triangles ABC and ADC

Hence answer is

the information that AC is perpendicular to BD is sufficient to complete the proof.

<u><em>Please give me brainliest as you promised you would!</em></u>

You might be interested in
HELPPPP<br> Which of the following is a solution of x2 + 5x = -2? (2 points)
harkovskaia [24]

Answer:

5.372 or −0.372

Step-by-step explanation:Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".

Step by step solution :

STEP

1

:

Trying to factor by splitting the middle term

1.1     Factoring  x2-5x-2

The first term is,  x2  its coefficient is  1 .

The middle term is,  -5x  its coefficient is  -5 .

The last term, "the constant", is  -2

Step-1 : Multiply the coefficient of the first term by the constant   1 • -2 = -2

Step-2 : Find two factors of  -2  whose sum equals the coefficient of the middle term, which is   -5 .

     -2    +    1    =    -1

     -1    +    2    =    1

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

1

:

 x2 - 5x - 2  = 0

STEP

2

:

Parabola, Finding the Vertex

2.1      Find the Vertex of   y = x2-5x-2

Parabolas have a highest or a lowest point called the Vertex .   Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) .   We know this even before plotting  "y"  because the coefficient of the first term, 1 , is positive (greater than zero).

Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two  x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.

Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.

For any parabola,Ax2+Bx+C,the  x -coordinate of the vertex is given by  -B/(2A) . In our case the  x  coordinate is   2.5000  

Plugging into the parabola formula   2.5000  for  x  we can calculate the  y -coordinate :

 y = 1.0 * 2.50 * 2.50 - 5.0 * 2.50 - 2.0

or   y = -8.250

Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = x2-5x-2

Axis of Symmetry (dashed)  {x}={ 2.50}

Vertex at  {x,y} = { 2.50,-8.25}

x -Intercepts (Roots) :

Root 1 at  {x,y} = {-0.37, 0.00}

Root 2 at  {x,y} = { 5.37, 0.00}

Solve Quadratic Equation by Completing The Square

2.2     Solving   x2-5x-2 = 0 by Completing The Square .

Add  2  to both side of the equation :

  x2-5x = 2

Now the clever bit: Take the coefficient of  x , which is  5 , divide by two, giving  5/2 , and finally square it giving  25/4

Add  25/4  to both sides of the equation :

 On the right hand side we have :

  2  +  25/4    or,  (2/1)+(25/4)

 The common denominator of the two fractions is  4   Adding  (8/4)+(25/4)  gives  33/4

 So adding to both sides we finally get :

  x2-5x+(25/4) = 33/4

Adding  25/4  has completed the left hand side into a perfect square :

  x2-5x+(25/4)  =

  (x-(5/2)) • (x-(5/2))  =

 (x-(5/2))2

Things which are equal to the same thing are also equal to one another. Since

  x2-5x+(25/4) = 33/4 and

  x2-5x+(25/4) = (x-(5/2))2

then, according to the law of transitivity,

  (x-(5/2))2 = 33/4

We'll refer to this Equation as  Eq. #2.2.1  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

  (x-(5/2))2   is

  (x-(5/2))2/2 =

 (x-(5/2))1 =

  x-(5/2)

Now, applying the Square Root Principle to  Eq. #2.2.1  we get:

  x-(5/2) = √ 33/4

Add  5/2  to both sides to obtain:

  x = 5/2 + √ 33/4

Since a square root has two values, one positive and the other negative

  x2 - 5x - 2 = 0

  has two solutions:

 x = 5/2 + √ 33/4

  or

 x = 5/2 - √ 33/4

Note that  √ 33/4 can be written as

 √ 33  / √ 4   which is √ 33  / 2

Solve Quadratic Equation using the Quadratic Formula

2.3     Solving    x2-5x-2 = 0 by the Quadratic Formula .

According to the Quadratic Formula,  x  , the solution for   Ax2+Bx+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                   

           - B  ±  √ B2-4AC

 x =   ————————

                     2A

 In our case,  A   =     1

                     B   =    -5

                     C   =   -2

Accordingly,  B2  -  4AC   =

                    25 - (-8) =

                    33

Applying the quadratic formula :

              5 ± √ 33

  x  =    —————

                   2

 √ 33   , rounded to 4 decimal digits, is   5.7446

So now we are looking at:

          x  =  ( 5 ±  5.745 ) / 2

Two real solutions:

x =(5+√33)/2= 5.372

or:

x =(5-√33)/2=-0.372

6 0
3 years ago
Identify the values a, b, and c is the first step in using the quadratic formula to find the solution(s) to a quadratic equation
zlopas [31]

The values are a = 7, b = -9, c = -18.

<u>Step-by-step explanation:</u>

The given quadratic equation is 7x^{2} - 9x = 18

The general form of the quadratic equation is ax^{2} + bx + c = 0

where,

  • a is the coefficient of x².
  • b is the coefficient of x.
  • c is the constant term.

Now, you have to modify the given quadratic equation similar to the general form of quadratic equation.

So, bring the constant term 18 to the left side of the equation for equating it to zero.

⇒ 7x^{2} - 9x - 18 = 0

Compare the above equation with general form ax^{2} + bx + c = 0

⇒ a = 7

⇒ b = -9

⇒ c = -18

Therefore, the values of a, b, and c are 7, -9 and -18.

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