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2 years ago

The equation of line AB is (y−3) = 5 (x − 4). What is the slope of a line perpendicular to line AB?

Mathematics

1 answer:

Darina [25.2K]2 years ago

8 0

Answer:

The perpendicular slope would be -1/5.

Step-by-step explanation:

This is because we can locate the slope of the original line as 5 (the number just outside of the x-coordinate parenthesis.

Then we know that perpendicular lines have opposite and reciprocal slopes. So we take the 5 and change the sign (-5), then we flip it (-1/5).

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Write an expression involving exponents to represent the shaded area in square inches of the diagram than use that expression to

Mazyrski [523]

The expression involving exponents to represent the shaded area in square inches of the diagram is: 6²- (3² + 2²). The shaded area in squares inches of the diagram is: 23 square inches.

<h3>Expression involving exponents and shaded area</h3>

The expression is:

6²- (3² + 2²)

The shaded area:

Shaded area=6²- (3² + 2²)

Shaded area=36-(9+4)

Shaded area=36-13

Shaded area=23 square inches

Therefore the expression involving exponents to represent the shaded area in square inches of the diagram is: 6²- (3² + 2²). The shaded area in squares inches of the diagram is: 23 square inches.

Learn more about Expression involving exponents and shaded area here:brainly.com/question/12529223

brainly.com/question/12560437

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6 0

1 year ago

If L || m, solve for x (9x+2) 119

algol13

Answer:

13.4

Step-by-step explanation:

(9x+2) 119 to solve for x you need to isolate it so subtract 119 so the equation would look like this (9x+2) = -119. Once you do that you are going to subtract 2 from both sides of the equation (9x)= -121. And now you divide by 9 and you have your answer x= 13.4.

6 0

2 years ago

If m<1=105 and m<4=115, then m<6=<br><br> A.75 B.40 C.50 D.60

RSB [31]

The answer is 40 so B

4 0

2 years ago

The sale rack at the department store said that an additional 30 percent discount would be taken on all items. If a dress

ryzh [129]

Answer:

$45.15

Step-by-step explanation:

Took both percents off, got it correct on the test.

4 0

3 years ago

Read 2 more answers

For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at

GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

$\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}$ $\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}$

Now, let's add the components of the same direction:

$\begin{gathered} V_x=W_x+A_x=35.35+0=35.35\\ \\ V_y=W_y+A_y=35.35-540=-504.65 \end{gathered}$

To find the resultant bearing (theta), we can use the formula below:

$\begin{gathered} \theta=\tan^{-1}(\frac{V_y}{V_x})\\ \\ \theta=\tan^{-1}(\frac{-504.65}{35.35})\\ \\ \theta=-86° \end{gathered}$

The angle -86° is equivalent to -86 + 360 = 274°.

Therefore the correct option is b.

8 0

1 year ago