Answer:
20
Step-by-step explanation:
In class 1, they used 10 sweet potatoes.
If they need 30, in class 2, they used 20.
just use what you know about this stuff
(a+36d)/(a+20d) = (a+55d)/(a+36d)
(a+36d)^2 = (a+55d)(a+20d)
a^2+72ad+1296d^2 = a^2+75ad+1100d^2
3ad = 196d^2
3a = 196d
That is, for any value of n,
a=196n
d=3n
So, there is no unique solution.
If n=1, then a=196 and d=3. The terms are
196+20*3 = 256
196+36*3 = 304
196+55*3 = 361
304/256 = 361/304
You can easily verify that it works for any value of n.
Hi friend,
If you flipped the graph y=x^2+2x-2 vertically, you would get the graph y=-(x^2+2x-2) TRUE.
Hope this helps you!
Answer:
0.761
Step-by-step explanation:the 7 is in the tenths the 6 is in the hundredths and the 1 is in the thousandths
Given:
The figure of two parallel lines MP and QS.
A transversal line KL interests the two parallel lines.
![m\angle KNM =146^\circ](https://tex.z-dn.net/?f=m%5Cangle%20KNM%20%3D146%5E%5Ccirc)
To find:
The
.
Solution:
If a transversal line intersect the two parallel lines, then the corresponding angles are congruent and their measures are equal.
In the given figure
and
corresponding angles. It means their measures are equal.
![m\angle KRQ=m\angle KNM](https://tex.z-dn.net/?f=m%5Cangle%20KRQ%3Dm%5Cangle%20KNM)
![m\angle KRQ=146^\circ](https://tex.z-dn.net/?f=m%5Cangle%20KRQ%3D146%5E%5Ccirc)
Therefore,
.