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kaheart [24]
3 years ago
9

Write two fractions where the LCD is 20, but the product of the denominators is not 20

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
5 0

Answer: \frac{1}{4} and  \frac{1}{10}

Step-by-step explanation:

To calculate the Least Common Denominator (LCD) of two fractions you must descompose each denominators into their prime factors and multiply the commons and non-commons with the largest exponent.

Let's write the following two fractions:

\frac{1}{4} and  \frac{1}{10}

The LCD is:

4=2*2=2^2\\10=2*5

LCD=2^2*5\\LCD=4*5\\LCD=20

So, we have two fractions where LCD is 20.

Let's verify that product of the denominators is not 20:

4*10=40 (The product is not 20).

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3 years ago
The radius of a right circular cylinder is increasing at a rate of 9 inches per minute and the height is decreasing at a rate of
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Answer:

\frac{dA}{dt}=1840.97 in^{2}/min      

Step-by-step explanation:

The equation of the surface of the right circular cylinder is:

A=2\pi rh+2\pi r^{2}=2\pi(rh+r^{2})

Now, the rate change of this area will be:

Using the change rule

\frac{dA}{dt}=\frac{\partial A}{\partial r}\frac{\partial r}{\partial t}+\frac{\partial A}{\partial h}\frac{\partial h}{\partial t}

Where:                          

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  • \frac{\partial r}{\partial t} is the rate change of radius (9 in/min)

 

\frac{dA}{dt}=\frac{\partial A}{\partial r}9+\frac{\partial A}{\partial h}(-16)

\frac{dA}{dt}=2\pi(h+2r)9-2\pi r16=2\pi((h+2r)9-16r)

Now, r = 16 and h = 29

\frac{dA}{dt}=2\pi((29+2*16)9-16*16)

\frac{dA}{dt}=1840.97 in^{2}/min      

I hope it helps you!

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Answer:

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Step-by-step explanation:

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Answer: 9


Step-by-step explanation:


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Read 2 more answers
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