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Reptile [31]
2 years ago
12

What is the radius of a hemisphere with a volume of 885 in^3, to the nearest tenth of an inch?

Mathematics
1 answer:
victus00 [196]2 years ago
4 0

Answer:

The desired radius is r = 7.5 inches

Step-by-step explanation:

The formula for the volume of a sphere of radius r is V = (4/3)πr³.  A hemisphere is half a full sphere, so the formula for the volume of a hemisphere of radius r is (4/3)(1/2)πr³, or (2/3)πr³.

We know that the volume of the hemisphere is 885 in³:

885 in³ = (2/3)πr³ and need to solve this first for r³ and then for r.

This is equivalent to:

885 in³ = (2π/3)r³.

We can now isolate r³ by multiplying both sides of this equation by (3 / [2π]):

(3 / [2π])(885 in³) = (3 / [2π])(2π/3)r³ = r³

Then r³ = 422.556 in³

Finally, we find the desired hemisphere radius by taking the cube root of both sides of the above equation:

r = ∛(422.556 in³) = 7.5 in (which is to the nearest tenth of an inch)

The desired radius is r = 7.5 inches

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Sedaia [141]

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To obtain a valid approximation for probabilities about the average daily downtime, either the underlying distribution(of the downtime per day for a computing facility) must be normal, or the sample size must be of 30 or more.

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In this question:

To obtain a valid approximation for probabilities about the average daily downtime, either the underlying distribution(of the downtime per day for a computing facility) must be normal, or the sample size must be of 30 or more.

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%20-%20354%20%3D%201221" id="TexFormula1" title="f - 354 = 1221" alt="f - 354 = 1221" align="
alukav5142 [94]

f-354=1221           <em>add 354 to both sides</em>

f+354-354=1221+354\\\\\boxed{f=1,575}\to\boxed{D.}

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Pick any term and subtract off the previous term to get the common difference.

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The positive common difference value indicates this arithmetic sequence is increasing.

6 0
2 years ago
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