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3 years ago

Can someone please help me with this?

Mathematics

2 answers:

Sidana [21]3 years ago

6 0

Answer:

Step-by-step explanation:

because the triangles are the same triangle AY is the same as XY and XZ is the same as AZ

e-lub [12.9K]3 years ago

3 0

The answer would be D) :)

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Explain whether a triangle exists with side lengths 31 m, 89 m, and 122 m.

ziro4ka [17]

Answer:

Step-by-step explanation:

The sum of the smaller sides is not bigger than the largest side, 122. ( 31 + 89 = 120 < 122)

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3 years ago

Are computers better than a straight edge and compass

serious [3.7K]

Answer:

Yes

Step-by-step explanation:

They are exact and you can't mess up or accidentally slide the compass or straightedge around. This is just my opinion though.

5 0

3 years ago

Read 2 more answers

A bag contains 10 red balls, 5 blue balls and 7 green balls. Find the probability of selecting at random

Masteriza [31]

Answer:

Probably red ball because it has higher amount

4 0

3 years ago

Read 2 more answers

What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{2};$
$5\cdot 4=20=\overline{7};$
$5\cdot 5=25=\overline{12};$
$5\cdot 6=30=\overline{4};$
$5\cdot 7=35=\overline{9};$
$5\cdot 8=40=\overline{1};$
$5\cdot 9=45=\overline{6};$
$5\cdot 10=50=\overline{11};$
$5\cdot 11=55=\overline{3};$
$5\cdot 12=60=\overline{8}.$

The multiplicative inverse of 5 in $Z_{13}$ is 8.

8 0

4 years ago

8. In a large population, 63% of the people have been vaccinated. If 4 people are randomly selected, what is the probability tha

Ludmilka [50]

The probability that none of the four have been vaccinated is
(1-0.63)^4 = 0.01874161

The probability that at least one has been vaccinated is the complement of this,
≈0.9813

3 0

3 years ago