An Ice Hockey rink is a rectangle with a perimeter of 174 meters. The length is 9 meters more than twice the width. What equatio
n describes this problem? (Remember that the perimeter is twice the length plus twice the width)
1 answer:
Answer:
Let width be x metres
so, length is "9 metres more than twice the width" --> 9+2x
So, perimeter is x + x + (9+2x) + (9+2x) = 174
6x + 18 = 174
6x = 156
x = 156/6
x = 26m
width = 26m
length is therefore 9+2(26) --> 9+52 --> 61m
Step-by-step explanation:
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