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Serga [27]
3 years ago
13

The radius of a circle is 14 meters. What is the circle circumference

Mathematics
1 answer:
seropon [69]3 years ago
5 0

Step-by-step explanation:

HERE,

redius of a circle (r)=14 meters.

we know that,

\boxed{\red{\sf{circle~ circumference=2\times \pi \times r   }}} 

<u>According</u><u> </u><u>to</u><u> </u><u>the question</u><u>, </u>

circle circumference=

  • \tt{2\times \pi \times 14   }

      

  • \tt{2 \times \dfrac{22}{7} \times 14   }  

    

  • \tt{2 \times \dfrac{22}{\cancel{7}} \times \cancel{14}}    

  

  • \tt{2\times 22 \times 2   }   

   

  • \tt{ 88~meters   }      

so, the circumference of that circle is <em><u>8</u></em><em><u>8</u></em><em><u> </u></em><em><u>meters</u></em><em><u>.</u></em>

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Step-by-step explanation:

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Read 2 more answers
Let u = (1, 2 -2), v= (2, 1, 3) and w = j + 4k. a) Find cos theta, where theta is the angle in degrees between u and w.
vodka [1.7K]

Answer: The value of cos theta is -0.352.

Step-by-step explanation:

Since we have given that

\vec{u}=1\hat{i}+2\hat{j}-2\hat{k}\and\\\\\vec{w}=\hat{j}+4\hat{k}

We need to find the cos theta between u and w.

As we know the formula for angle between two vectors.

\cos\ \theta=\dfrac{\vec{u}.\vec{w}}{\mid u\mid \mid w\mid}

So, it becomes,

\cos \theta=\dfrac{2-8}{\sqrt{1^2+2^2+(-2)^2}\sqrt{1^2+4^2}}\\\\\cos \theta=\dfrac{-6}{\sqrt{17}\sqrt{17}}=\dfrac{-6}{17}=-0.352\\\\\theta=\cos^{-1}(\dfrac{-6}{17})=110.66^\circ

Hence, the value of cos theta is -0.352.

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3 years ago
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