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san4es73 [151]
3 years ago
8

What is 692,040 rounded to nearest hundred

Mathematics
1 answer:
Leviafan [203]3 years ago
8 0

it would be 692,000 even though it may look odd since the place holder for 100 is a 0

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Which equation represents direct variation, if k represents the constant of variation? A) y = kx B) yx = k C) y = kx2 D) y = kxz
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Y = kx

the question ask for "direct vation"...the formula must always to be y at the left side and k at the right side
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3 years ago
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[(-3)+9] × [(-10)-(-9)]<br>please solve this​
exis [7]
[(-3)+9] × [(-10)-(-9)]

6 × (-10 + 9)

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2 years ago
Which product is better to buy small 18 ounces for $3.25 or large 32 ounces for 5.50
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Answer:

the 32 ounce is the better buy

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Consider the parabola r​(t)equalsleft angle at squared plus 1 comma t right angle​, for minusinfinityless thantless thaninfinity
kodGreya [7K]

Given:-   r(t)=< at^2+1,t>  ; -\infty < t< \infty , where a is any positive real number.

Consider the helix parabolic equation :  

                                              r(t)=< at^2+1,t>

now, take the derivatives we get;

                                            r{}'(t)=

As, we know that two vectors are orthogonal if their dot product is zero.

Here,  r(t) and r{}'(t)  are orthogonal i.e,   r\cdot r{}'=0

Therefore, we have ,

                                  < at^2+1,t>\cdot < 2at,1>=0

< at^2+1,t>\cdot < 2at,1>=

                                              =2a^2t^3+2at+t

2a^2t^3+2at+t=0

take t common in above equation we get,

t\cdot \left (2a^2t^2+2a+1\right )=0

⇒t=0 or 2a^2t^2+2a+1=0

To find the solution for t;

take 2a^2t^2+2a+1=0

The numberD = b^2 -4ac determined from the coefficients of the equation ax^2 + bx + c = 0.

The determinant D=0-4(2a^2)(2a+1)=-8a^2\cdot(2a+1)

Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola  r(t)=< at^2+1,t> i.e <1,0>




                                               




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Answer:

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